According to the table, the rock MOST LIKELY found floating in the water after the eruption of Krakatoa Volcano would be
1 answer:
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A) See ray diagram in attachment (-6.0 cm)
By looking at the ray diagram, we see that the image is located approximately at a distance of 6-7 cm from the lens. This can be confirmed by using the lens equation:
where
q is the distance of the image from the lens
f = -10 cm is the focal length (negative for a diverging lens)
p = 15 cm is the distance of the object from the lens
Solving for q,
B) The image is upright
As we see from the ray diagram, the image is upright. This is also confirmed by the magnification equation:
where are the size of the image and of the object, respectively.
Since q < 0 and p > o, we have that , which means that the image is upright.
C) The image is virtual
As we see from the ray diagram, the image is on the same side of the object with respect to the lens: so, it is virtual.
This is also confirmed by the sign of q in the lens equation: since q < 0, it means that the image is virtual
Answer:
458.33 ft
Explanation:
We are given that
Wavelength of of an x- ray photon=1 in
Wavelength of of an x- ray photon==ft
1 in=feet
We have to find the length of line (in feet) drawn by you to represent the wavelength of visible light.
According to question
Wavelength of visible light= ft
Wavelength of visible lightft
Wavelength of visible light=458.33 ft
Hence, the 458.33 ft line must drawn by you to represent the wavelength of visible light.