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Elden [556K]
3 years ago
7

According to the table, the rock MOST LIKELY found floating in the water after the eruption of Krakatoa Volcano would be

Physics
1 answer:
statuscvo [17]3 years ago
4 0

D) pumice.

Explanation:

The rock that most likely floats on water after the eruption of Krakatoa volcano is a Pumice.

Pumice is the only rock that floats on water. It's density is less than that of water and so, it will stay afloat.

  • From the given options, pumice is the only extrusive igneous rock. Volcanic eruptions are extrusive in nature.
  • Granite is an intrusive plutonic rock
  • Phyllite and marble are metamorphic rocks.

learn more:

Sedimentary rocks brainly.com/question/2740663

#learnwithBrainly

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Maya uses a tuning fork of frequency 250 Hz to produce transverese waves on a stretched string. Her friend justin measure the di
Goshia [24]

Answer:

The velocity of the wave is 12.5 m/s

Explanation:

The given parameters are;

he frequency of the tuning fork, f = 250 Hz

The distance between successive crests of the wave formed, λ = 5 cm = 0.05 m

The velocity of a wave, v = f × λ

Where;

f = The frequency of the wave

λ = The wavelength of the wave - The distance between crests =

Substituting the known values gives;

v =  250 Hz × 0.05 m = 12.5 m/s

The velocity of the wave, v = 12.5 m/s.

6 0
3 years ago
An object is 15 cm in front of a diverging lens with a
Rainbow [258]

A) See ray diagram in attachment (-6.0 cm)

By looking at the ray diagram, we see that the image is located approximately at a distance of 6-7 cm from the lens. This can be confirmed by using the lens equation:

\frac{1}{q}=\frac{1}{f}-\frac{1}{p}

where

q is the distance of the image from the lens

f = -10 cm is the focal length (negative for a diverging lens)

p = 15 cm is the distance of the object from the lens

Solving for q,

\frac{1}{q}=\frac{1}{-10 cm}-\frac{1}{15 cm}=-0.167 cm^{-1}

q=\frac{1}{-0.167 cm^{-1}}=-6.0 cm

B) The image is upright

As we see from the ray diagram, the image is upright. This is also confirmed by the magnification equation:

h_i = - h_o \frac{q}{p}

where h_i, h_o are the size of the image and of the object, respectively.

Since q < 0 and p > o, we have that h_i >0, which means that the image is upright.

C) The image is virtual

As we see from the ray diagram, the image is on the same side of the object with respect to the lens: so, it is virtual.

This is also confirmed by the sign of q in the lens equation: since q < 0, it means that the image is virtual

4 0
4 years ago
The wavelength of visible light is about 5500 times longer than the wavelength of x-rays. If you represent the wavelenth of an x
Pie

Answer:

458.33 ft

Explanation:

We are given that

Wavelength of of an x- ray photon=1 in

Wavelength of of an x- ray photon==\frac{1}{12}ft

1 in=\frac{1}{12}feet

We have to find the  length of line (in feet) drawn by you to represent the wavelength of visible light.

According to question

Wavelength of visible light=5500\times \frac{1}{12} ft

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Wavelength of visible light=458.33 ft

Hence, the 458.33 ft line must drawn  by you to represent the wavelength of visible light.

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