Question

A horizontal clothesline is tied between 2 poles, 16 meters apart. When a mass of 3 kilograms is tied to the middle of the clothesline, it sags a distance of 3 meters. What is the magnitude of the tension on the ends of the clothesline? NOTE: Use g=9.8m/s2 for the gravitational acceleration.

Answer 1

Answer:

T=mg

m=3 Kg

g=9,8 m/s^2

T=3*9.8

T=29.4 Kg/m^2

Answer 2

Answer:

The magnitude of the tension on the ends of the clothesline is 41.85 N.

Explanation:

Given that,

Poles = 2

Distance = 16 m

Mass = 3 kg

Sags distance = 3 m

We need to calculate the angle made with vertical by mass

Using formula of angle

$\tan\theta=\dfrac{8}{3}$

$\thta=\tan^{-1}\dfrac{8}{3}$

$\theta=69.44^{\circ}$

We need to calculate the magnitude of the tension on the ends of the clothesline

Using formula of tension

$mg=2T\cos\theta$

Put the value into the formula

$3\times9.8=2T\times\cos69.44$

$T=\dfrac{3\times9.8}{2\times\cos69.44}$

$T=41.85\ N$  

Hence, The magnitude of the tension on the ends of the clothesline is 41.85 N.