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Trava [24]
3 years ago
13

How is the moon's position in a total solar eclipse different from its position in an annular eclipse? Please write in your own

words
Physics
1 answer:
Savatey [412]3 years ago
4 0

Answer:

The difference of the moons position when a solar eclipse happens is it is closer to earth when a annular eclipse happens it is farther away from earth.

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A 1.60 m cylindrical rod of diameter 0.550 cm is connected to a power supply that maintains a constant potential difference of 1
bija089 [108]

1.

Answer:

Part a)

\rho = 1.35 \times 10^{-5}

Part b)

\alpha = 1.12 \times 10^{-3}

Explanation:

Part a)

Length of the rod is 1.60 m

diameter = 0.550 cm

now if the current in the ammeter is given as

i = 18.7 A

V = 17.0 volts

now we will have

V = I R

17.0 = 18.7 R

R = 0.91 ohm

now we know that

R = \rho \frac{L}{A}

0.91 = \rho \frac{1.60}{\pi(0.275\times 10^{-2})^2}

\rho = 1.35 \times 10^{-5}

Part b)

Now at higher temperature we have

V = I R

17.0 = 17.3 R

R = 0.98 ohm

now we know that

R = \rho \frac{L}{A}

0.98 = \rho' \frac{1.60}{\pi(0.275\times 10^{-2})^2}

\rho' = 1.46 \times 10^{-5}

so we will have

\rho' = \rho(1 + \alpha \Delta T)

1.46 \times 10^{-5} = 1.35 \times 10^{-5}(1 + \alpha (92 - 20))

\alpha = 1.12 \times 10^{-3}

2.

Answer:

Part a)

i = 1.55 A

Part b)

v_d = 1.4 \times 10^{-4} m/s

Explanation:

Part a)

As we know that current density is defined as

j = \frac{i}{A}

now we have

i = jA

Now we have

j = 1.90 \times 10^6 A/m^2

A = \pi(\frac{1.02 \times 10^{-3}}{2})^2

so we will have

i = 1.55 A

Part b)

now we have

j = nev_d

so we have

n = 8.5 \times 10^{28}

e = 1.6 \times 10^{-19} C

so we have

1.90 \times 10^6 = (8.5 \times 10^{28})(1.6 \times 10^{-19})v_d

v_d = 1.4 \times 10^{-4} m/s

8 0
4 years ago
URGENT: write a simple equation relating the frequency (f) of a wave to its period (T)
EastWind [94]

Answer:

f(x) = mx + b

Explanation:

5 0
3 years ago
The amount of energy invested into glycolysis is ____________ atp
Liono4ka [1.6K]
The amount of energy invested into glycolysis is 2 ATP.


3 0
3 years ago
THE ONE WHO WILL ANSWER IT CORRECT WILL BE MARKED AS "BRAINLIST"....... If the radius of the orbit of a spaceship from the centr
jonny [76]

Answer:

Explanation:

19116 being the distance from the centre of the earth to the point you want to check in metres. So after all that you get G = 1.0888m/second squared. Hope that helps you/ you should be able to pop in any height you want.

plz mark as brainliest

5 0
3 years ago
MARKING BRAINLIEST! The velocity of sound waves in air is 343 m/s, 1,007 m/s in helium and 267 m/s in carbon dioxide. Which one
FromTheMoon [43]

Answer:

In helium

Explanation:

Since the units are the same, the value should only be considered.

6 0
3 years ago
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