Answer:
L' = 555.95 lb
Explanation:
Analyzing the given conditions in the question, we get
The safe load, L is directly proportional to width (w) and square of depth (d²)
also,
L is inversely proportional length (l) i.e L = k/l
combining the above conditions, we get an equation as:
L = k(wd²/l)
now, for the first case we have been given
w = 3 in
d = 6 in
l = 11 ft
L = 1213 lbs
thus,
1213 lb = k ((3 × 6²)/11)
or
k = 123.54 lbs/(ft.in³)
Now,
Using the calculated value of k to calculate the value of L in the second case
in the second case, we have
w = 6 in
d =3 in
l = 12 ft
Final Safe load L' = 123.54 × (6 × 3²/12)
or
L' = 555.95 lb
Answer:
t = 180 / 1.4 = 129 sec (time to swim horizontally across river)
S = 129 sec * V where V is speed of current and S is the distance he will be carried downstream
The problem does not specify V the speed of the river
Answer: 1) 17.65 * 10^-12 C/V; 2) 0.68 V
Explanation: In order to calculate the capacitance of one cylinder capacitor we have to use the following expression:
where and b are the inner and outer radius of teh cylinder, respectively. L is length of the cylinder.
Finally we also kwn that C=Q/ΔV
then we have
ΔV =Q/C
ΔV = 12 * 10^-12/17.65*10^-12= 0.68V
Her magnitude of deceleration on the ice would be 15.126m/s
