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navik [9.2K]
3 years ago
12

Transfer RNA __________. A is translated into protein B tags a growing polypeptide for export to the endoplasmic reticulum C is

produced in the nucleolus D has catalytic activity and is thus a ribozyme E binds to its specific amino acid in the active site of an aminoacyl-tRNA synthetase
Chemistry
1 answer:
Mashutka [201]3 years ago
7 0
The answer is E. The function of t RNA is to transfer aminoacids into ribosomes for protein synthesis. Aminoacyl-tRNA synthetase is the enzyme that binds the related aminoacids into trna for transfer. What determines which aminoacids will be transferred into ribosomes is the codons on mRNA.
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Find the number of kilograms in 15.40 moles of C5H10O5
OLga [1]
C5H10O5 would weight a total of 2.312 kilograms.
5 0
3 years ago
A car moves at a speed of 50 kilometers/hour. Its kinetic energy is 400 joules. If the same car moves at a speed of 100 kilomete
lys-0071 [83]

ke prop to v^2


ke1/v1^2=ke2/v2^2


400/50x50=joules/100x100


400x2x2


1600j

8 0
3 years ago
What is the correct formula
nataly862011 [7]

Answer:

A the answer is A I'm sure

7 0
3 years ago
HURRY HELP 10 POINTS ILL GOVE BRAINLIEST I HAVE TO PASS PICTURE PROVIDED
kramer

Answer:

C₃H₄O₄

Explanation:

In order to get the empirical formula of a compound, we have to follow a series of steps.

Step 1: Divide the percent by mass of each element by its atomic mass.

C: 34.6/12.01 = 2.88

H: 3.9/1.01 = 3.86

O: 61.5/16.00 = 3.84

Step 2: Divide all the numbers by the smallest one, i.e., 2.88

C: 2.88/2.88 = 1

H: 3.86/2.88 ≈ 1.34

O: 3.84/2.88 ≈ 1.33

Step 3: Multiply all the numbers by a number that makes all of them integer

C: 1 × 3 = 3

H: 1.34 × 3 = 4

O: 1.33 × 3 = 4

The empirical formula is C₃H₄O₄.

5 0
3 years ago
Why is the answer C for this problem?
pshichka [43]

Answer:

\boxed{\text{(C) X}$_{3}$P$_{2}}

Explanation:

Step 1. Identify the Group that contains X

We look at the consecutive ionization energies and hunt for a big jump between them

\begin{array}{crc}n & IE_{n} & IE_{n} - IE_{n-1}\\1 & 730 & \\2 & 1450 & 720\\3 & 7700 & 6250\\4 & 10500 & 2800\\\end{array}

We see a big jump between n = 2 and n = 3. This indicates that X has two valence electrons.

We can easily remove two electrons, but the third electron requires much more energy. That electron must be in the stable, filled, inner core.

So, X is in Group 2 and P is in Group 15.

Step 2. Identify the Compound

X can lose two valence electrons to reach a stable octet, and P can do the same by gaining three electrons.

We must have 3 X atoms for every 2 P atoms.

The formula of the compound is \boxed{\text{X}$_{3}$P$_{2}}$}.

4 0
3 years ago
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