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erastovalidia [21]
3 years ago
6

The element copper has naturally occurring isotopes with mass numbers of 63 and 65. The relative abundance and atomic masses are

69.2% for a mass of 62.93 amu and 30.8% for a mass of 64.93amu. Calculate the average atomic mass of copper.
Chemistry
1 answer:
timofeeve [1]3 years ago
4 0

Answer:

63.546

Explanation:

The Average atomic mass is calculated using the formula:

sum of the product of the atomic masses and their relative abundances all divided by 100 or total abundance

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NikAS [45]

Answer:

carbon = 7 atoms

hydrogen = 8 atoms

nitrogen = 4 atoms

oxygen = 2 atoms

Explanation:

Chemical formula = C₇H₈N₄O₂

Elements present:

carbon

hydrogen

nitrogen

oxygen

Number of atoms of each element.

carbon = 7 atoms

hydrogen = 8 atoms

nitrogen = 4 atoms

oxygen = 2 atoms

6 0
3 years ago
WILL MARK BRAINLIEST
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Answer:

b) 590

Explanation:

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Aluminum chloride, AlCl3, is an inexpensive reagent used in many industrial processes. It is made by treating scrap aluminum wit
mylen [45]

Answer:

83.8%

Explanation:

The balanced reaction equation is;

2Al(s) + 3Cl2(g) → 2AlCl3(s)

Now we have to obtain the limiting reactant as the reactant that produces the least amount of AlCl3

Amount of Al = 3.11g/27 g/mol = 0.115 moles

If 2 moles of Al yields 2 moles of  AlCl3

Then 0.115 moles of Al yields 0.115 moles of  AlCl3

For Cl2

Amount of Cl2 = 5.32 g/71 g/mol= 0.075 moles

If 3 moles of Cl2 yields 2 moles of  AlCl3

0.075 moles of Cl2 yields 0.075   * 2/3 = 0.05 moles of  AlCl3

Hence Cl2 is the limiting reactant

Theoretical yield of  AlCl3 = 0.05 moles of  AlCl3 * 133g/mol = 6.65 g

%yield = actual yield /theoretical yield * 100

%yield = 5.57 g/6.65 g * 100

%yield = 83.8%

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2 years ago
Which element has the strongest attraction for electrons?
NemiM [27]

Answer:

The answer is Flourine

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Some forms of vitamin D, C₂₈H₄₄O, can be found in red meat. How many total atoms are in 5 molecules of C₂₈H₄₄O
MaRussiya [10]

Answer:

3.01 × 10^24 atoms of vitamin D

Explanation:

The number of atoms, molecules or ions present in a substance is given by the Avogadro's number which is 6.02 × 10^23.

Hence;

1 molecule of vitamin D contains 6.02 ×10^23 atoms

5 molecules of vitamin D contains 5 × 6.02 ×10^23/1

= 3.01 × 10^24 atoms of vitamin D

7 0
3 years ago
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