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erastovalidia [21]
3 years ago
6

The element copper has naturally occurring isotopes with mass numbers of 63 and 65. The relative abundance and atomic masses are

69.2% for a mass of 62.93 amu and 30.8% for a mass of 64.93amu. Calculate the average atomic mass of copper.
Chemistry
1 answer:
timofeeve [1]3 years ago
4 0

Answer:

63.546

Explanation:

The Average atomic mass is calculated using the formula:

sum of the product of the atomic masses and their relative abundances all divided by 100 or total abundance

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Which of the following is the best example of an open system? (2 points)
Dmitriy789 [7]
1) A Car engine.............. Hope it helps, Have a nice day :)
5 0
3 years ago
Read 2 more answers
In an experiment, hydrochloric acid reacted with different volumes of sodium thiosulfate in water. A yellow precipitate was form
erastovalidia [21]

Answer:

The time taken for the cross mark to disappear decreases steadily down the column.

Explanation:

Now if we look at the data provided, we will discover that the volume of the HCl was held constant while the volume of the thiosulphate was increased steadily and the volume of water decreased steadily.

Recall that a system is more concentrated when it contains less volume of water and more volume of reactants. Hence as the volume of water in the system is being reduced, the concentration of reactants is increased.

It has been established that an increase in the concentration of reactants lead to an increase in the rate of reaction. The disappearance of the cross shows the completion of the reaction between HCl and thiosulphate. The faster or slower the cross disappears, the faster or slower the rate of reaction.

Since increase in concentration of reactants increases the rate of reaction, it is observed that as the volume of the thiosulphate increases (reactant concentration increases) the cross disappears faster (rate of reactant increases). Hence as the volume of thiosulphate increases, it takes a shorter time for the cross to disappear. This implies that the time column in the table (refer to the question) will decrease steadily as the volume of thiosulphate increases.

5 0
3 years ago
Which statement best describes the structure of covalent network solids? A. They are giant structures held together by weak forc
konstantin123 [22]

Answer: Option (B) is the correct answer.

Explanation:

A covalent compound is a compound formed by sharing of electrons. And, in a covalent network solid atoms are bonded by covalent bonds in a continuous network that is extending throughout the material or solid.

This continuous arrangement of atoms are like a lattice.

For example, diamond is a covalent network solid in which carbon atoms are arranged in a continuous lattice like structure.

Hence, we can conclude that the statement all the atoms are covalently bonded to other atoms to form a lattice-like structure, best describes the structure of covalent network solids.

6 0
3 years ago
A ball is moving at a speed of 6.70 m/s. If the kinetic energy of the ball is 3.10 J, what is the mass of the ball?​
Anni [7]

Answer:

<h2>0.14 kg</h2>

Explanation:

The mass of the ball can be found by using the formula

m =  \frac{2k}{ {v}^{2} }  \\

v is the velocity

k is the kinetic energy

From the question we have

m =  \frac{2(3.10)}{ {6.70}^{2} }  =  \frac{6.20}{44.89}  \\  = 0.138115...

We have the final answer as

<h3>0.14 kg</h3>

Hope this helps you

7 0
3 years ago
HI decomposes to H2 and I2 by the following equation: 2HI(g) → H2(g) + I2(g);Kc = 1.6 × 10−3 at 25∘C If 1.0 M HI is placed into
dsp73

<u>Answer:</u> The concentration of hydrogen gas at equilibrium is 0.037 M

<u>Explanation:</u>

We are given:

Initial concentration of HI = 1.0 M

The given chemical equation follows:

                       2HI(g)\rightleftharpoons H_2(g)+I_2(g)

<u>Initial:</u>               1.0

<u>At eqllm:</u>        1.0-2x          x           x

The expression of K_c for above equation follows:

K_c=\frac{[H_2][I_2]}{[HI]^2}

We are given:

Kc=1.6\times 10^{-3}

Putting values in above expression, we get:

1.6\times 10^{-3}=\frac{x\times x}{(1.0-2x)^2}\\\\x=-0.043,0.037

Neglecting the negative value of 'x' because concentration cannot be negative

So, equilibrium concentration of hydrogen gas = x = 0.037 M

Hence, the concentration of hydrogen gas at equilibrium is 0.037 M

6 0
3 years ago
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