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erastovalidia [21]
3 years ago
6

The element copper has naturally occurring isotopes with mass numbers of 63 and 65. The relative abundance and atomic masses are

69.2% for a mass of 62.93 amu and 30.8% for a mass of 64.93amu. Calculate the average atomic mass of copper.
Chemistry
1 answer:
timofeeve [1]3 years ago
4 0

Answer:

63.546

Explanation:

The Average atomic mass is calculated using the formula:

sum of the product of the atomic masses and their relative abundances all divided by 100 or total abundance

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Match the chemical with the statement that best describes the observed change in the rate of the reaction when the concentration
maria [59]

Answer:

Explanation:

When the amount of H2O2 is doubled while KI is kept constant, the rate of reaction doubles.

When the amount of KI is doubled and the amount of H2O2 is halved, the rate stays nearly constant.

2H2O2 (aq) → O2(g) + 2H2O (l) ------------- first order kinetics reaction.

Catalysts are KI, FeCl3 only, KCl is not a catalyst. Order: KI < MnO2 < Pb < FeCl3.

H2O2 + I– -> IO– + H2O (Step 1)

H2O2 + IO– -> I– + H2O + O2 (Step 2)

It can be seen that the iodine ion (provided by the KI solution) is a product as well as a reactant.

02(g)2Fe? (aq) + 2 H(a) 2 H 2 Fe3 (aq) H2O2(aq) + 2 Fe,Taq) H02(aq) 2 Fe (aq) 2 H (aq)

8 0
2 years ago
What type of tide is produced when earth is directly between the sun and the moon?
Yuki888 [10]
High tide or Neap tides which are normally really high.
4 0
3 years ago
Calculate the amount of grams of water that was used when 5525J of energy was used to boil this amount of water.
djverab [1.8K]

Answer:

2.445 g

Explanation:

Step 1: Given and required data

  • Energy in the form of heat required to boil the water (Q): 5525 J
  • Latent heat of vaporization of water (∆H°vap): 2260 J/g
  • Mass of water (m): ?

Step 2: Calculate the mass of water

We will use the following expression.

Q = ∆H°vap × m

m = Q / ∆H°vap

m = 5525 J / (2260 J/g)

m = 2.445 g

4 0
2 years ago
Identify ALL the possible mol ratio from<br> this balanced equation:
grandymaker [24]

Answer:

\frac{1 mole of N_{2} }{3 moles of H_{2} }

Explanation:

The equation of the reaction:

   Nitrogen gas N₂ reacts with Hydrogen as H₂ to produce ammonia NH₃;

 

          N₂    +    H₂    →    NH₃  

 The balanced equation is ;

        N₂    +    3H₂    →    2NH₃  

The mole ratio is the ratio of the coefficients of the combining reactants;

   1 mole of N₂ combines with 3 mole of H₂;

So;

      \frac{1 mole of N_{2} }{3 moles of H_{2} }

3 0
2 years ago
The total amount of energy before and after a chemical reaction is the same. Therefore, energy is _____
ANTONII [103]

Answer:

The total amount of energy before and after a chemical reaction is the same. Thus, energy is Question 14 options: the same as mass.

Explanation:

5 0
2 years ago
Read 2 more answers
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