Answer:
One number, let's call it x, is 6 more than twice the other number, let's say this number is y.
x= 2y+6
x+y=21
We're left with a system of equations.
If we substitute the first equation in the second we find the value of y.
(2y+6)+y=21
3y+6=21
3y=15
<u><em>y=5</em></u>
Now that we have found the value of y, we can take that value and substitute it in the second equation (since it's easier) to find the value of x.
x+ (5)=21
<u><em>x=16</em></u>
<u><em>Now to check if our answers are correct, we plug in both values into any equation and see if they equate.</em></u>
x+y=21
(16)+(5)=21
21=21
Our solution is correct!
Answer:
Step-by-step explanation:
Answer:
The number of solutions of the system is 0
Step-by-step explanation:
we know that
When solving a system of equations by graphing, the solution of the system is equal to the intersection point both graphs.
In this problem the graphs do not intersect
therefore
The number of solutions of the system is 0
