In ΔDEF, the measure of ∠F=90°, the measure of ∠D=66°, and EF = 32 feet. Find the length of FD to the nearest tenth of a foot.
1 answer:
Answer:
14.2 ft
Step-by-step explanation:
tan 66° = 32/ FD
FD = 32 / tan 66° = 32 / 2.246 = 14.2
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W is 17. Hope i was able to help
Answer:
![14250.26{in}^{3}](https://tex.z-dn.net/?f=14250.26%7Bin%7D%5E%7B3%7D)
Step-by-step explanation:
For a cylinder:
![v=\pi{r}^{2}h](https://tex.z-dn.net/?f=v%3D%5Cpi%7Br%7D%5E%7B2%7Dh)
where v is the volume, r is the radius of the cylinder, and h is the height.
![v=\pi({12}^{2})(31.5)=\bold{14250.26{in}^{3} }](https://tex.z-dn.net/?f=v%3D%5Cpi%28%7B12%7D%5E%7B2%7D%29%2831.5%29%3D%5Cbold%7B14250.26%7Bin%7D%5E%7B3%7D%20%7D)
2.3+3.1+1= 6.4
25÷6.4= 3.90625
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