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3 years ago

Given that x =4 and y= 1 over 2, find the value of 2x²- 3xy

Mathematics

2 answers:

jarptica [38.1K]3 years ago

7 0

Answer:

Step-by-step explanation:

Lubov Fominskaja [6]3 years ago

6 0

Step-by-step explanation:

given that x=4 and y=1/2

2*4*4 - 3*4*(1/2) = 32 - 6 = 26

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g Suppose a factory production line uses 3 machines, A, B, and C for making bolts. The total output from the line is distributed

Vladimir [108]

Answer:

The probability that it came from A, given that is defective is 0.362.

Step-by-step explanation:

Define the events:

A: The element comes from A.

B: The element comes from B.

C: The element comes from C.

D: The elemens is defective.

We are given that P(A) = 0.25, P(B) = 0.35, P(C) = 0.4. Recall that since the element comes from only one of the machines, if an element is defective, it comes either from A, B or C. Using the probability axioms, we can calculate that

$P(D) = P(A\cap D) + P(B\cap D) + P(C\cap D)$

Recall that given events E,F the conditional probability of E given F is defined as

$P(E|F) = \frac{P(E\cap F)}{P(F)}$ , from where we deduce that

$P(E\cap F) = P(E|F)P(F)$ .

We are given that given that the element is from A, the probability of being defective is 5%. That is P(D|A) =0.05. Using the previous analysis we get that

$P(D) = P(A)P(D|A)+P(B) P(D|B) + P(C)P(D|C) = 0.05\cdot 0.25+0.04\cdot 0.35+0.02\cdot 0.4 = 0.0345$

We are told to calculate P(A|D), then using the formulas we have

$P(A|D) = \frac{P(A\cap D)}{P(D)}= \frac{P(D|A)P(A)}{P(D)}= \frac{0.05\cdot 0.25}{0.0345}= 0.36231884$

3 0

2 years ago

32 lb 12 ounces equals in pounds

Radda [10]

Answer:

32 3/4 lb

Step-by-step explanation:

32 lb 12 oz = ? lb

Rewrite 12 oz as (12/16) lb.

Then:

32 lb 12 oz = 32 lb + (3/4) lb, or 32 3/4 lb

4 0

2 years ago

Deluxe River Cruises operates a fleet of river vessels. The fleet has two types of vessels: A type-A vessel has 60 deluxe cabins

bixtya [17]

Answer: It should be used 2 for type-A and 3 for type-B to minimize the cost.

Step-by-step explanation: As it is stipulated, <u>x</u> relates to type-A and y to type-B.

Type-A has 60 deluxe cabins and B has 80. It is needed a minimum of 360 deluxe cabins, so:

60x + 80y ≤ 360

For the standard cabin, there are in A 160 and in B 120. The need is for 680, so:

160x + 120y ≤ 680

To calculate how many of each type you need:

60x + 80y ≤ 360

160x + 120y ≤ 680

Isolating x from the first equation:

x = $\frac{360 - 80y}{60}$

Substituing x into the second equation:

160( $\frac{360 - 80y}{60}$ ) + 120y = 680

-3200y+1800y = 10200 - 14400

1400y = 4200

y = 3

With y, find x:

x = $\frac{360 - 80y}{60}$

x = $\frac{360 - 80.3}{60}$

x = 2

To determine the cost:

cost = 42,000x + 51,000y

cost = 42000.2 + 51000.3

cost = 161400

To keep it in a minimun cost, it is needed 2 vessels of Type-A and 3 vessels of Type-B, to a cost of $161400

8 0

2 years ago

A group of friends were working on a student film that had a budget of $700. They

Ipatiy [6.2K]

Answer:

231

Step-by-step explanation:

subtract 700 by 469

4 0

2 years ago

F(x) = x2 – 2x + 3; f(x) = -x + 5

creativ13 [48]

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8 0

3 years ago