Team infinite dimensions canoed 15 and 3/4 miles in 3 hours.What was their average rate of speed in miles per hour

Please help me, if you help then thanks!

vredina [299]

The formula for volume always involves three dimensions.

In this case, the volume of a cube is $V=s^3$ , where $s$ is the side length of the cube.

To solve for that side length, you'd need to use a cube root.

8 0

3 years ago

Need help FAST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

vova2212 [387]

Answer:

Right angle 90 degrees is always going to be a right angle.

Step-by-step explanation:

8 0

2 years ago

Help me with this please I will give you Brainliest

oksian1 [2.3K]

Answer

h = 8.12 cm

Explanation

Area of a parallelogram = b • h

We know the area is 20.3 cm^2 and that the base is 2.5cm.

Therefore 20.3 cm^2 = 2.5h

20.3/2.5 = 8.12 cm

h = 8.12 cm

3 0

3 years ago

Christine Wong has asked Dave and Mike to help her move into a new apartment on Sunday morning. She has asked them both in case

olga nikolaevna [1]

Answer:

(a) The probability that both Dave and Mike will show up is 0.25.

(b) The probability that at least one of them will show up is 0.75.

(c) The probability that neither Dave nor Mike will show up is 0.25.

Step-by-step explanation:

Denote the events as follows:

D = Dave will show up.

M = Mike will show up.

Given:

$P(D^{c})=0.55\\P(M^{c})=0.45$

It is provided that the events of Dave of Mike showing up are independent of each other.

(a)

Compute the probability that both Dave and Mike will show up as follows:

$P(D\cap M)=P(D)\times P (M)\\=[1-P(D^{c})]\times [1-P(M^{c})]\\=[1-0.55]\times[1-0.45]\\=0.2475\\\approx0.25$

Thus, the probability that both Dave and Mike will show up is 0.25.

(b)

Compute the probability that at least one of them will show up as follows:

P (At least one of them will show up) = 1 - P (Neither will show up)

$=1-P(D^{c}\cup M^{c})\\=P(D\cup M)\\=P(D)+P(M)-P(D\cap M)\\=[1-P(D^{c})]+[1-P(M^{c})]-P(D\cap M)\\=[1-0.55]+[1-0.45]-0.25\\=0.75$

Thus, the probability that at least one of them will show up is 0.75.

(c)

Compute the probability that neither Dave nor Mike will show up as follows:

$P(D^{c}\cup M^{c})=1-P(D\cup M)\\=1-P(D)-P(M)+P(D\cap M)\\=1-[1-P(D^{c})]-[1-P(M^{c})]+P(D\cap M)\\=1-[1-0.55]-[1-0.45]+0.25\\=0.25$

Thus, the probability that neither Dave nor Mike will show up is 0.25.

6 0

3 years ago

Read 2 more answers

Boyd’s dartboard is octagonal. Each side measures 9 in. He drew a copy of the board that was smaller by a scale factor 0.25.

Basile [38]

The question is about the side length of a copy of the dartboard. We know that the original dartboard has sides that measure 9 inches. We also have the scale factor 0.25. The ratio of the corresponding sides is called the scale factor. If we have the scale factor 0.25 it means that for 1 unit of the original figure there are 0.25 units of length of a copy. Therefore: x = 9 * 0.25; x = 2.25 in. Answer: The side length of the dartboard Boyd drew is 2.25 inches.

5 0

3 years ago