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aivan3 [116]
3 years ago
15

Identify the initial amount a and the growth factor b in the exponential function.

Mathematics
1 answer:
alina1380 [7]3 years ago
7 0

Given the equation A (x) = 30 x 8.3 ^x, we can get the initial amount of A when x is equal to zero. Therefore:

A (0) = 30 * 8.3^0

A (0) = 30

In this case the equation grows by 8.3 times as x increases. Therefore the growth factor is 8.3.

Answers:

initial amount = 30

growth factor = 8.3

The answers are not in the given choices. I believe you are giving the wrong equation. If the correct equation here is:

A (x) = 680 x 4.3 ^x 

Then the answers are:

initial amount = 680

growth factor = 4.3

The answers are now in the choices given.

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jeyben [28]
4 - (x+2) < -3(x+4)

4 -1(x) -1(2) < -3(x) -3(4)
4 - x - 2 < -3x -12
 <u>  +3x        +3x      </u>
<u />2 + 2x    <   -12
<u>-2                   -2    
</u>      2x     < -14
<u /> <u>     ÷2          ÷2    </u>
        x      < -7

assume that x = -8

4 - (-8 + 2) < -3(-8 + 4)
4 - (-6) < -3(-4)
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10 < 12  the inequality is true.
8 0
3 years ago
Lindsay is 5 years younger than Mark. Seven years ago, the sum of their ages was 31.
Rashid [163]

Answer:

The present age of Mark is 25 years.

And present age of Lindsay is  20 years.

Step-by-step explanation:

Let us assume:

The present age of Lindsay = l

The present age of Mark = m

⇒ Age of Lindsay seven years ago =  (l -7) years

and Age of Mark seven years ago =  (m -7) years

According to question:

Lindsay is 5 years younger than Mark    ⇒   l = m  - 5

Seven years ago, the sum of their ages was 31  ⇒  (l-7) + (m -7)  = 31

So, the given set of equation are:

l = m  - 5    .........  (1)

(l-7) + (m -7)  = 31

⇒ ((m - 5) -7) + (m -7)  = 32  (from (1)

or, m -12 + m - 7  = 31

or, 2m = 31 + 19 = 50

⇒ m = 50 / 2  = 25, or m  = 25

Hence,the present age of Mark = 25 years

So,the present age of Lindsay = 25 - 5 = 20 years

7 0
3 years ago
A ball is thrown from an initial height of 2 feet with an initial upward velocity of 33/fts. The ball's height h (in feet) after
RoseWind [281]

Answer:

t=1.283 seconds and

0.779 seconds

Step by step Explanation:

Given: h=18 ft

The given equation is h=2+33t-16t²

Then if we substitute the value of given h, h=18 ft into the given equation we have,

18=2+33t-16t²

Then if we re- arrange we have

16t²−33t+16=0

We can see that the above quadratic equation is in standard form, with a=16, b=33 and c=16 then we can use quadratic formula in solving it which is

t= −(−33±√[(−33) ²−4×16×16)]/(2×16)

= [33±√[1089−1024]/(32)

= [33±√[65]/(32)

=1.283 or 0.779 seconds

the two real roots , of the quadratic are:

1.283 and

0.779 seconds

t= 1.283 or 0.779 seconds

Hence, the ball is at 18 feet with height 0.779seconds after it has been thrown up and,

and is at 21 feet with height 1.283 seconds after after thrown down

4 0
3 years ago
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Temka [501]
Y = 18x

Y = Miles
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5 0
3 years ago
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fiasKO [112]

Answer:

6ft 3in

Step-by-step explanation:


5 0
4 years ago
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