Let the required equation be y = mx + c; where y = 1, m = f'(0), x = 0
f(a) = sec(a)
f'(a) = sec(a)tan(a)
f'(0) = sec(0)tan(0) = 0
y = mx + c
1 = 0(0) + c
c = 1
Therefore, required equation is
y = 1.
What is your question?
(Please don report me, im just trying to help, really)
If theres supposed to be a picture, i dont see anything btw.
<span>statements is not true
</span><span>D. -a = c
-a should be equal d, not c</span>
F(x) = kx
12 = 8k
k = 12/8 = 3/2
Required equation is f(x) = 3/2 x
