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3 years ago

Help please!

Mathematics

1 answer:

DENIUS [597]3 years ago

3 0

Answer:

i would make a number line up to 10. the with a hollow dot on -4 have a line facing left

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Solve the following system y=-2 -2x-7y=24

Dafna1 [17]

Answer:

x = -5

y = -2

Step-by-step explanation:

<em><u>Since you have y, plug that into the equation:</u></em>

-2x - 7y = 24

-2x - 7(-2) = 24

-2x + 14 = 24

<u><em>Then, subtract 14 from both sides:</em></u>

-2x + 14 = 24

- 14 - 14

__________

-2x = 10

<u><em>Finally, divide both sides by -2:</em></u>

-2x = 10

x = -5

So now you have, x = -5 and y = -2.

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3 years ago

How many solutions does this linear system have? y = y equals StartFraction 2 over 3 EndFraction x plus 2. X 2 6x – 4y = –10 one

nordsb [41]

The system of equations provides a unique solution(one solution) at (-0.6, 1.6).

<h2>Given to us,</h2>

$y=\dfrac{2}{3}x+2$
$6x-4y=-10$

<h3>Equation 2</h3>

As we already have the value of y from equation 1, substitute its value in equation 2,

$6x-4y=-10$

$6x-4(\dfrac{2}{3}x+2)=-10$

$6x-\dfrac{8}{3}x-8=-10$

$\dfrac{6x}{1}-\dfrac{8}{3}x=-10+8$

$\dfrac{6x\times 3}{1\times 3}-\dfrac{8}{3}x=-2$

$\dfrac{18x-8x}{3}=-2$

$10x=-6\\$

$x=\dfrac{-6}{10} \\\\x=-0.6$

<h3>Equation 1,</h3>

$y=\dfrac{2}{3}x+2$

substitute the value of x in equation 1,

$y=\dfrac{2}{3}(\dfrac{-6}{10})+2\\\\y = \dfrac{-2}{5}+2\\\\y= \dfrac{-2+10}{5}\\\\y = \dfrac{8}{5}\\\\y=1.6$

As we can see the system of equations provides a unique solution(one solution) at (-0.6, 1.6).

Learn more about the system of equations:

brainly.com/question/12895249

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What is the correct expanded for and value of 43?

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Answer:

A and C

Step-by-step explanation:

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Step-by-stHEep explanation:

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