Answer:
$850
Explanation:
Price per share = $6,000 ÷1,000 = $6
Number of shares repurchased = $900 ÷$6 = $150
New number of shares outstanding = $1,000 - $150 = $850
Therefore $850 shares of stock will be outstanding after the stock repurchase is completed
Answer:
$0.70 per stock
Explanation:
before tax corporate income = $2.50 per stock
after tax corporate income = $2.50 x (1 - 30%) = $1.75 per stock
distributed dividends = $1.75 x 50% = $0.875 per stock
since the tax rate on dividends is 20%, then the after tax gain earned by stockholders is $0.875 x (1 - 20%) = $0.70 per stock
Some dividends are taxed as long term capital gains (like these), which decreases the tax rate paid by stockholders. If they were taxed at the normal income rate, the tax rate would have been 8% higher.
Answer:
Total unitary cost= $4,800
Explanation:
Giving the following information:
Actual units= 800
Total fixed costs= 1,000*800= 800,000
UNitary variable cost= $4,000
Units increase= 200
<u>On unitary bases, variable costs remain constant. On the contrary, fixed costs vary at a unitary level. Now, the same amount of costs is divided by a larger number of units.</u>
<u></u>
Unitary fixed overhead= 800,000/1,000= $800
Total unitary cost= 4,000 + 800= $4,800
Answer:
Safety signs and symbols are important safety communicating tools, they help to indicate various hazards that present in plant site or workplace. At the same time, they warn workers to always keep watching out for those hazards by giving required information and safety instructions.
Explanation:
hope this helps you
Answer:
Explanation:
I think your question is missed of key information, allow me to add in and hope it will fit the original one. Please have a look at the attached photo.
Given:
- Cost $71 per linear foot
- Budge $34080 for those walls
Let X is the the length
Let Y is the width
From the photo, we can see that
(4X + 6Y)*71 = 34080
<=> (4X + 6Y) = 480
<=> Y = 80 - 
X
The are of the rectangular industrial warehouse:
A(X) = 3Y*X
<=> A(X) = 3(80 - X )X
<=>A(X) = (240-2X)X = 240X - 
So A'(X) = 240 - 4X
Let A'(X) = 0, we have:
240 - 4X = 0
<=> X = 60
=> Y =(80 - X ) = 80 - *60 = 40
So the dimension to maximize total area is: 60 in length and 40 in width
