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Sunny_sXe [5.5K]
3 years ago
14

The profit that the vendor makes per day by selling x pretzels is given by the function. P(x) = -0.002x2 + 1.4x - 400. Find the

number of pretzels that must be sold to maximize profit.
Business
1 answer:
amm18123 years ago
7 0

Answer:

350 the number of pretzels that must be sold to maximize profit.

Explanation:

P(x) = -0.002x2 + 1.4x - 400

Differentiating P(x) with respect to dx:

P(x)'=\frac{d(-0.002x2 + 1.4x - 400)}{dx}

P(x)'=-2\times 0.002x+1.4

Putting , P(x)' =0

0=-0.004x+1.4

x=\frac{1.4}{0.004}=350

we get , x = 350

Differentiating P(x)' with respect to dx:

P(x)''=-0.004

P(x)''<0 (maxima)

350 the number of pretzels that must be sold to maximize profit.

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Explanation:

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