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baherus [9]
2 years ago
10

Morgan earned $70.00 at her job when she worked for 4 hours. How much money did she earn each hour?

Mathematics
1 answer:
Mila [183]2 years ago
4 0

Answer:

divide the 70.00 by the four hours

Step-by-step explanation:

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If 8a + 7b + c = 9, what is -6c - 48a - 42b
maksim [4K]

Answer:

-54

Step-by-step explanation:

8a + 7b + c = 9

We want -6c, but we have c in the equation so multiply by -6

-6(8a + 7b + c) = 9*-6

-48a -42b -6c = -54

Rearranging the equation

-6c - 48a - 42b = -54

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That it satisfies x = 0

Step-by-step explanation:

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A CBS News/New York Times opinion poll asked 1,190 adults whether they would prefer balancing the federal budget over cutting ta
nikklg [1K]

Using the <u>normal distribution and the central limit theorem</u>, it is found that there is a 0.0166 = 1.66% probability of a sample proportion of 0.59 or less.

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.  
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
  • By the Central Limit Theorem, the sampling distribution of sampling proportions of a proportion p in a sample of size n has mean \mu = p and standard error s = \sqrt{\frac{p(1 - p)}{n}}

In this problem:

  • 1,190 adults were asked, hence n = 1190
  • In fact 62% of all adults favor balancing the budget over cutting taxes, hence p = 0.62.

The mean and the standard error are given by:

\mu = p = 0.62

s = \sqrt{\frac{p(1 - p)}{n}} = \sqrt{\frac{0.62(0.38)}{1190}} = 0.0141

The probability of a sample proportion of 0.59 or less is the <u>p-value of Z when X = 0.59</u>, hence:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{0.59 - 0.62}{0.0141}

Z = -2.13

Z = -2.13 has a p-value of 0.0166.

0.0166 = 1.66% probability of a sample proportion of 0.59 or less.

You can learn more about the <u>normal distribution and the central limit theorem</u> at brainly.com/question/24663213

7 0
2 years ago
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