Answer:
A, C, and E
Step-by-step explanation:
For the first one, distribute -11 to each value. A negative times a negative is a positive, so -11×-2c is 22c. -11×-3d is 33d. So the first one is right. For the third one, distribute 1/3 to each value. 1/3 of 66c is 22c, and 1/3 of 99d is 33d, so the third one is correct as well. For the last one, distribute 11 again. 11×2c is 22c and 11×3d is 33d, so the last one is correct.
The answer is y =3x
Explaining
y= 3*-3
y=-9
Answer:
i) is irrational and ii) is rational
Step-by-step explanation:
i) does not keep a consistent pattern. If it was .11011011011.... it would be a rational number, but since it keeps changing its pattern it would be considered irrational. ii) is rational because it has a consistent pattern that doesn't change.
The answer is 36/49.
You take the second fraction and flip it (it will be 12/14) and you multiply straight across. You get 72/98. You simplify it by finding it's greatest common factor (in this case it is 2) so you divide it the numerator and the denominator by 2. You get 36/49.
Step-by-step explanation:
I assume that "ground" is at 0 ft height. which is in an actual scenario not airways the case.
y = -16x² + 64x + 89
shows us that the tower is 89 ft tall (the result for x = 0, at the start).
anyway, if the original assumption is correct, then we need to solve
0 = -16x² + 64x + 89
the general solution for such a quadratic equation is
x = (-b ± sqrt(b² - 4ac))/)2a)
in our case
a = -16
b = 64
c = 89
x = (-64 ± sqrt(64² - 4×-16×89))/(2×-16) =
= (-64 ± sqrt(4096 + 5696))/-32 =
= (-64 ± sqrt(9792))/-32
x1 = (-64 + 98.95453501...)/-32 = -1.092329219... s
x2 = (-64 - 98.95453501...)/-32 = 5.092329219... s
the negative solution for time is but useful here (it would be the time calculated back to ground at the start).
so, x2 is our solution.
the rocket hits the ground after about 5.09 seconds.
