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yarga [219]
3 years ago
12

6p = -42 what is the answer???????????

Mathematics
2 answers:
Inga [223]3 years ago
8 0

Answer:

Hey there!

Step 1:

6p =  - 42

Write the equation

Step 2:

p =  \frac{ - 42}{6}

take 6 to other side to divide it with-42

p =  - 7

after dividing 6 with -42 we will get -7

\small{\purple {\sf \underline{hope\: it\: helped\: you✿}}}

Rina8888 [55]3 years ago
4 0
<h3>Given Equation:</h3>

6p = -42

<h3>To Find:</h3>

The value of p.

<h3>Solution:</h3>

6p = -42

or, p = -42/6

or, p = -7

<h2>Answer:</h2>

The value of p is -7.

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Quadrilateral ABCD is inscribed. The measure of ∠A=67°. What is the measure of ∠C?
WARRIOR [948]

Answer:

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3 years ago
Calculate the annual return percentage
xenn [34]
The annual return percentages will be evaluated using the formula:
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a] A=$500, P=$400, n=1 years
500=400(1+r)^1
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1.25=1+r
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b] A=2500+100=$2600, P=$ 2000, n=1 year
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5 0
3 years ago
pls help will give brainliest Rena used the steps below to evaluate the expression (StartFraction (x Superscript negative 3 Base
kaheart [24]

Answer:

  First "order of operations" mistake: step 2

  First arithmetic mistake: step 4

Step-by-step explanation:

As we understand Rena's work, she wants to simplify ...

  \left(\dfrac{x^{-3}y^{-2}}{2x^4y^{-4}}\right)^{-3}

for x = -1 and y = 2.

Her work seems to be ...

<u>Step 1</u>

  \text{Substitute $x=-1$ and $y=2$ into the expression}\\\\\left(\dfrac{(-1)^{-3}2^{-2}}{2(-1)^42^{-4}}\right)^{-3}\qquad\text{no error}

<u>Step 2</u>

  \text{Simplify the parentheses}\\\\\left(\dfrac{2^4}{2(-1)^4(-1)^32^2}\right)^{-3}=\left(\dfrac{2^2}{2(-1)^7}\right)^{-3}\qquad\text{order of operations error}

<u>Step 3</u>

  \text{Evaluate the power to a power}\\\\\dfrac{2^{-6}}{2^{-3}(-1)^{21}}\qquad\text{no error}

<u>Step 4</u>

  \text{Use reciprocals and find the value}\\\\\dfrac{1}{2^32^6(-1)^{21}}=\dfrac{1}{8\cdot 64\cdot (-1)}=\dfrac{-1}{512}\qquad\text{error: $2^3$ is used instead of $2^{-3}$}

_____

So, the first arithmetic error is in Step 4. However, the order of operations requires exponents be evaluated first. Doing that makes step 2 look like ...

  \left(\dfrac{-\dfrac{1}{4}}{2(1)\dfrac{1}{16}}\right)^{-3}=(-2)^{-3}\qquad\text{proper Step 2}

__

We expect your answer is supposed to be Step 4.

7 0
3 years ago
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