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uranmaximum [27]
2 years ago
11

What is it's momentum?

Mathematics
2 answers:
saveliy_v [14]2 years ago
7 0

Step-by-step explanation:

The variables are p= unknown, m= 30000 kg and the velocity = 25 m/s.

We can use equation,

p = mv

Where m is the mass, and v is the velocity and p is the momentum.

We plug in the known.

p = (30000)(25)

p = 750000

Remeber the units so we get

p=750000 kg m/s or 7.5 E5 kg m/s

Aliun [14]2 years ago
5 0

\huge \boxed{ \sf  Solution}

  • Mass of the truck (m) = 30000 Kg
  • Velocity (v) = 25 m/s
  • Let the momentum be p.
  • We know, momentum = mass × velocity
  • Therefore, the momentum of the truck (p)
  • = mv
  • = (30000 × 25) Kg m/s
  • = 750000 Kg m/s

<u>Answers</u><u>:</u>

<u>Variable </u><u>:</u><u> </u><u>m,</u><u> </u><u>v,</u><u> </u><u>p</u>

<u>Equation </u><u>:</u><u> </u><u>p </u><u>=</u><u> </u><u>mv</u>

<u>Answer:</u><u> </u><u>The momentum of the truck is 750000 Kg m/s.</u>

Hope you could understand.

If you have any query, feel free to ask.

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For the following telescoping series, find a formula for the nth term of the sequence of partial sums {Sn}. Then evaluate limn→[
Ivenika [448]

Answer:

The following are the solution to the given points:

Step-by-step explanation:

Given value:

1) \sum ^{\infty}_{k = 1} \frac{1}{k+1} - \frac{1}{k+2}\\\\2) \sum ^{\infty}_{k = 1} \frac{1}{(k+6)(k+7)}

Solve point 1 that is \sum ^{\infty}_{k = 1} \frac{1}{k+1} - \frac{1}{k+2}\\\\:

when,

k= 1 \to  s_1 = \frac{1}{1+1} - \frac{1}{1+2}\\\\

                  = \frac{1}{2} - \frac{1}{3}\\\\

k= 2 \to  s_2 = \frac{1}{2+1} - \frac{1}{2+2}\\\\

                  = \frac{1}{3} - \frac{1}{4}\\\\

k= 3 \to  s_3 = \frac{1}{3+1} - \frac{1}{3+2}\\\\

                  = \frac{1}{4} - \frac{1}{5}\\\\

k= n^  \to  s_n = \frac{1}{n+1} - \frac{1}{n+2}\\\\

Calculate the sum (S=s_1+s_2+s_3+......+s_n)

S=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+.....\frac{1}{n+1}-\frac{1}{n+2}\\\\

   =\frac{1}{2}-\frac{1}{5}+\frac{1}{n+1}-\frac{1}{n+2}\\\\

When s_n \ \ dt_{n \to 0}

=\frac{1}{2}-\frac{1}{5}+\frac{1}{0+1}-\frac{1}{0+2}\\\\=\frac{1}{2}-\frac{1}{5}+\frac{1}{1}-\frac{1}{2}\\\\= 1 -\frac{1}{5}\\\\= \frac{5-1}{5}\\\\= \frac{4}{5}\\\\

\boxed{\text{In point 1:} \sum ^{\infty}_{k = 1} \frac{1}{k+1} - \frac{1}{k+2} =\frac{4}{5}}

In point 2: \sum ^{\infty}_{k = 1} \frac{1}{(k+6)(k+7)}

when,

k= 1 \to  s_1 = \frac{1}{(1+6)(1+7)}\\\\

                  = \frac{1}{7 \times 8}\\\\= \frac{1}{56}

k= 2 \to  s_1 = \frac{1}{(2+6)(2+7)}\\\\

                  = \frac{1}{8 \times 9}\\\\= \frac{1}{72}

k= 3 \to  s_1 = \frac{1}{(3+6)(3+7)}\\\\

                  = \frac{1}{9 \times 10} \\\\ = \frac{1}{90}\\\\

k= n^  \to  s_n = \frac{1}{(n+6)(n+7)}\\\\

calculate the sum:S= s_1+s_2+s_3+s_n\\

S= \frac{1}{56}+\frac{1}{72}+\frac{1}{90}....+\frac{1}{(n+6)(n+7)}\\\\

when s_n \ \ dt_{n \to 0}

S= \frac{1}{56}+\frac{1}{72}+\frac{1}{90}....+\frac{1}{(0+6)(0+7)}\\\\= \frac{1}{56}+\frac{1}{72}+\frac{1}{90}....+\frac{1}{6 \times 7}\\\\= \frac{1}{56}+\frac{1}{72}+\frac{1}{90}+\frac{1}{42}\\\\=\frac{45+35+28+60}{2520}\\\\=\frac{168}{2520}\\\\=0.066

\boxed{\text{In point 2:} \sum ^{\infty}_{k = 1} \frac{1}{(n+6)(n+7)} = 0.066}

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Answer:

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B) gabby will catch up with Miguel in 2 hours at a distance of 60 miles

Step-by-step explanation:

<u><em>Lets start of with the equation:</em></u>

There is 2 possible equations we can use for this:

  1. A) Miguel: d=25t+10  gabby: d=30t     OR
  1. D) Miguel: d=10t+25  gabby: d= 30t

The resonable response for this would be A because Miguel starts off with 10 miles so you would add 10 to your equation so response D is incorrect because you are not multiplying 10t, but rather 25t.

<u><em>Now let's do the actual answer</em></u>

There is 2 possible answer for this:

  1. B) gabby will catch up with Miguel in 2 hours at a distance of 60 miles
  2. C) gabby will catch up with Miguel in 1.25 at a distance of 37.5 miles

The response that would make the most sense would be B. Let me explain

We are going to be using response C for now. You would have to multiply Miguel: 25(1.25) + 10

31.25 + 10

=41.25

Gabby: 30(1.25)

= 37.50

Miguel is still ahead of Gabby so Answer C is incorrect

We are going to be using response B now. You would have to multiply

Miguel: 25(2) + 10

50 + 10

=60

Gabby: 30(2)

=60

Now they are both the same mile so this would mean Answer B is correct

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Answer:

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Step-by-step explanation:

refer to attached graphic

the formula for compound interest is given as

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where

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t = 1 year

substituting these values into the equation

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A = $13,952.30

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