Question

What is the area of Figure ABCD?

Answer 1

Answer:

The area of Figure ABCD is:

                          120 square inches.

Step-by-step explanation:

We know that the figure is the shape of a trapezoid .

and we know that the area of trapezoid is given by:

$Area=\dfrac{1}{2}\times (sum\ of\ the\ bases)\times Height$

i.e. If B and B' are two bases of the trapezoid and H is the height of the trapezoid then,

$Area=\dfrac{1}{2}\times (B+B')\times H$

Here in the figure we have:

$B=17\ inches$

$B'=13\ inches$

$H=8\ inches$

Hence, the area of figure is:

$Area=\dfrac{1}{2}\times (13+17)\times 8\\\\i.e.\\\\Area=\dfrac{1}{2}\times 30\times 8\\\\Area=120\ \text{square\ inches}$

Answer 2

Area of the rectangle is L * W.......13 * 8 = 104 sq in.

Area of a triangle is (h * b) / 2......(8 * 4) / 2 = 32/2 = 16 sq. in.

104 + 16 = 120 sq. in. <===