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olga_2 [115]
3 years ago
5

Which is bigger 2/3 or 3/5?

Mathematics
1 answer:
Lunna [17]3 years ago
3 0
2/3 is bigger because it is smaller in fraction size.
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What two numbers equal the absolute value of 15
Drupady [299]

There is only one number that is equal to the absolute value of  15.
That number is  15.

But wait !

There are two different numbers WHOSE ABSOLUTE VALUES
are both  15.

Those numbers are  15  and  -15 .

3 0
3 years ago
Expand.<br> If necessary, combine like terms.<br> (3 + 4x) (3 - 4x)
shepuryov [24]
  • (3 + 4x) (3 - 4x)

We know the algebraic identity: (a - b)(a + b) = a^2 + b^2. Therefore, we should square 3 and 4x.

  • = (3)^2 - (4x)^2
  • 9 - 16x^2

<u>Answer</u><u>:</u>

<u>9</u><u> </u><u>-</u><u> </u><u>1</u><u>6</u><u>x</u><u>^</u><u>2</u>

Hope you could understand.

If you have any query, feel free to ask

5 0
2 years ago
20 Is 80 percent of what number?<br> A 21<br> В 22<br> С 24<br> D 25
gogolik [260]

Answer:

D. 25

Step-by-step explanation:

If this helps, please mark this as brainliest

6 0
3 years ago
Read 2 more answers
at the amusement park each student is given $16 for food this covers the cost of two meals plus $4 for snacks how much money doe
Igoryamba
(16 - 4) ÷ 2
This would give you $6, so that is how much they expect you to spend per meal.
5 0
3 years ago
In ΔABC, the lengths of a, b, and c are 22.5 centimeters, 18 centimeters, and 13.6 centimeters, respectively.
Irina-Kira [14]
Given the values of the three sides of the triangle, we can apply the Cosine Law to find the angles of the triangle. Recall that for we can express the value of c through the equation below.

c^{2} = a^{2} + b^{2} - 2abcosC

Rearranging this equation, we can find the value ∠C as shown below.

\cos C = \frac{a^{2}+b^{2}-c^{2}}{2ab}
C = cos^{-1} (\frac{a^{2}+b^{2}-c^{2}}{2ab})

We can apply the same reasoning for finding the value of ∠B as shown.

B = cos^{-1} (\frac{a^{2}+c^{2}-b^{2}}{2ac})

Plugging in the values of the sides (see image attached) from the given. It will now be straightforward to compute for ∠B and ∠C.

C = cos^{-1} (\frac{22.5^{2}+18^{2}-13.6^{2}}{2(22.5)(18)})
C \approx 37.19

B = cos^{-1} (\frac{22.5^{2}+13.6^{2}-18^{2}}{2(22.5)(13.6)})
B \approx 53.13

Answer: ∠C = 37.19° and ∠B = 53.13°

7 0
4 years ago
Read 2 more answers
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