Carbon dioxide = CO2
.5 mol CO2 = 1 mol O
1 mol O = <span><u>6.022140857 × 10^23 Oxygen atoms</u></span>
Answer:
2 L is the new volume
Explanation:
We can apply the Ideal Gases Law to solve the problem.
At STP, we kwow that 1 mol of gas occupy a volume of 22.4 L
Then, how many moles do we have in 1 L?
Let's do it by a rule of three:
(1L . 1 mol) / 22.4L = 0.0446 moles
These moles are at 1 atm and 273 K of temperature, so let's change our conditions.
P . V = n . R .T
1 atm . V = 0.0446 mol . 0.082 L.atm/mol K . 546 K
V = 2 L
If we pay attention, we can notice that, if we double temperature, we double the volume.
Answer:
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Explanation:
according to the formula...
density =mass/ volume...
density =21.0/2.00=10.5 g/ cm^3