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Phoenix [80]
2 years ago
10

A chemist measures the amount of fluorine gas produced during an experiment. He finds that of fluorine gas is produced. Calculat

e the number of moles of fluorine gas produced.
Chemistry
1 answer:
Debora [2.8K]2 years ago
3 0

Answer:

12.7 mol

Explanation:

<em>A chemist measures the amount of fluorine gas produced during an experiment. He finds that 482. g of fluorine gas is produced. Calculate the number of moles of fluorine gas produced.</em>

Step 1: Given data

Mass of fluorine (m): 482. g

Step 2: Determine the molar mass (M) of fluorine

Fluorine is a diatomic molecule of chemical formula F₂. Its molar mass is:

mF₂ = 2 × mF = 2 × 19.00 g/mol = 38.00 g/mol

Step 3: Determine the number of moles (n) corresponding to 482. g of fluorine

We will use the following expression,.

n = m/M

n = 482. g/(38.00 g/mol)

n = 12.7 mol

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The molecule CO2 is arranged in a linear molecular geometry. TRUE FALSE
antiseptic1488 [7]

I would say true because the Valence Shell Electron Pairs will Repel each other. When they do they are forced to the opposite side of the Carbon atom giving CO2 a linear molecular shape. The CO2 bond angle will be 180 degrees since it has a linear molecular geometry.

sorry if im wrong

5 0
3 years ago
22. Radon has a half-life of 3.83 days. How long will it take a 225 g sample to decay to 14.06 g? (3pts.)
prohojiy [21]

Answer:

15.32 days

Explanation:

From the question given above, the following data were obtained:

Half-life (t½) = 3.83 days

Original amount (N₀) = 225 g

Amount remaining (N) = 14.06 g

Time (t) =.?

Next, we shall determine the number of half-lives that has elapsed. This can be obtained as follow:

Original amount (N₀) = 225 g

Amount remaining (N) = 14.06 g

Number of half-lives (n) =?

N = N₀ / 2ⁿ

14.06 = 225 / 2ⁿ

Cross multiply

14.06 × 2ⁿ = 225

Divide both side by 14.06

2ⁿ = 225 / 14.06

2ⁿ = 16

Express 16 in index form with 2 as the base

2ⁿ = 2⁴

n = 4

Thus, 4 half-lives has elapsed.

Finally, we shall determine the time. This can be obtained as follow:

Half-life (t½) = 3.83 days

Number of half-lives (n) = 4

Time (t) =.?

n = t / t½

4 = t / 3.83

Cross multiply

t = 4 × 3.83

t = 15.32 days

Therefore the time for 225 g sample of Radon to decay to 14.06 g is 15.32 days

8 0
2 years ago
Ethyne gas combusts with oxygen gas according to the following reaction: Calculate the volume, in mL of CO2 produced when 73 g o
Bezzdna [24]

Answer: Volume of CO2 is 89127 mL

Explanation: The reaction that takes place is: C2H2 + O2 --> CO2 + H2O

The amount of C2H2 that react allow us to predict the amount of CO2 that will be obtained

mol CO2 = 73gC2H2 .\frac{1 mol C2H2}{26gC2H2} . \frac{2mol CO2}{4mol C2H2} = 5,6 mol CO2

26g/1mol is molar mass of C2H2 and 2/4 is the molar relation between CO2 and C2H2 in this reaction. Canceling units, at the end mol of CO2 are obtained

Now with the moles of CO2 and the ideal gases equation is possible to calculate the volumen occupied by the gas.

PV = RnT where P: pressure, V: volume, R: ideal gas constant, n: moles and T: temperature expressed in K (add 273,15 to °C temperature: 37,4°C + 273,15 = 310,55K)

V= RnT/P

V= \frac{0,08206 atmL/molK . 5,6 mol. 310,55 K}{1,6 atm}  =89,127 L

To express volume in mL multiply the L result by 1000 which equals 89127 mL

5 0
3 years ago
.92 moles of carbon dioxide, CO2, was produced when you burned C6H120. (glucose) with O2.
Radda [10]

Answer:

16.56g.

Explanation:

You need to compare the number of coefficient of the reaction product to find how much water produced. The reaction formula will produce 6 carbon dioxide(CO2) and 6 water (H2O).

If the reaction produces 0.92 moles of carbon dioxide, then the amount of water produced in moles will be: 0.92 moles * (6/6)= 0.92 moles

The molar mass of water is 18g/mol, so the calculation of moles to mass will be: 0.92 moles * (18g/mol)= 16.56g.

6 0
3 years ago
A solution which is ____ will dissolve in a solvent, like water. A) freezing B) insoluble C) combustible D) soluble
shtirl [24]

Answer:

I think it may be b but I am not sure

3 0
3 years ago
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