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alexdok [17]
4 years ago
5

Can i solve an addition to different variables

Mathematics
1 answer:
Yuliya22 [10]4 years ago
8 0

Answer:

no unless the variables are known

Step-by-step explanation:

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PLEASE HELP ME FOR BRAINLIEST!!!!
saul85 [17]

Answer:

29

Step-by-step explanation:

90+61=151, so angle B would be 29 degrees

8 0
3 years ago
Read 2 more answers
Jorge has some dimes and quarters. He has 10 more dimes than quarters and the collection of coins is worth $2.40. How many dimes
PIT_PIT [208]

Answer:

14 dimes and 4 quarters

Step-by-step explanation:

x= number of dimes

y=number of quarters

x-10=y

0.10x+0.25y=2.40

substitute for y

0.10x+0.25(x-10)=2.40

0.35x-2.50=2.40

0.35x=4.90

x=14

y=4

5 0
3 years ago
supervisor records the repair cost for 25 randomly selected dryers. A sample mean of $93.36 and standard deviation of $19.95 are
Simora [160]
<h2><u>Answer with explanation:</u></h2>

The confidence interval for population mean (when population standard deviation is unknown) is given by :-

\overline{x}-t^*\dfrac{s}{\sqrt{n}}< \mu

, where n= sample size

\overline{x} = Sample mean

s= sample size

t* = Critical value.

Given : n= 25

Degree of freedom : df=n-1=24

\overline{x}= \$93.36

s=\ $19.95

Significance level for 98% confidence interval : \alpha=1-0.98=0.02

Using t-distribution table ,

Two-tailed critical value for 98% confidence interval :

t^*=t_{\alpha/2,\ df}=t_{0.01,\ 24}=2.4922

⇒ The critical value that should be used in constructing the confidence interval = 2.4922

Then, the 95% confidence interval would be :-

93.36-(2.4922)\dfrac{19.95}{\sqrt{25}}< \mu

=93.36-9.943878< \mu

=93.36-9.943878< \mu

=83.416122< \mu

Hence, the 98% confidence interval for the mean repair cost for the dryers. = 83.4161

4 0
3 years ago
Help please :)
Marta_Voda [28]
If you are given 25 gallons, then all u have to do is multiply 25 by 2.369
and the answer is $59.225
5 0
3 years ago
Read 2 more answers
If AD is an altitude of ABC, then
serg [7]

Answer:

ADB is C. 90 degrees.

4 0
3 years ago
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