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3 years ago

Simplify 2(x + 4) + 3(x - 4

1 answer:

3 0

Answer:=5x−4 =(2)(x)+(2)(4)+(3)(x)+(3)(−4)=2x+8+3x+−12Combine Like Terms:=2x+8+3x+−12=(2x+3x)+(8+−12)=5x+−4

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PLEASE HELP WITH THE FIRST 3 parts

PIT_PIT [208]

Answer:

a) x = -2+√3 and -2-√3

b) x = -1 + 2√3/3 and -1 - 2√3/3

c) x = 3.185 and 0.315

Step-by-step explanation:

To solve the following quadratic equation, we will use the general formula

x = -b±√b²-4ac/2a

a) x²+4x+1 = 0

a = 1, b = 4 and c = 1

Substitute into the formula

x = -4±√4²-4(1)(1)/2(1)

x = -4±√16-4/2

x = -4±√12/2

x = -4±2√3/2

x = (-4+2√3)/2 and (-4-2√3)/2

x = -2+√3 and -2-√3

b) 3x²+6x-1 = 0

a = 3, b = 6 and c = -1

Substitute into the formula

x = -6±√6²-4(3)(-1)/2(3)

x = -6±√36+12/6

x = -6±√48/6

x = -6±4√3/6

x = (-6+4√3)/6 and (-6-4√3)/6

x = -1 + 2√3/3 and -1 - 2√3/3

c) 2x² - 7x + 2 = 0

a = 2, b = -7 and c = 2

x = -(-7)±√(-7)²-4(2)(2)/2(2)

x = 7±√49-16/4

x =7±√33/4

x = 7±5.74/4

x = 7+5.74/4 and 7-5.74/4

x = 12.74/4 and 1.26/4

x = 3.185 and 0.315

4 0

3 years ago

3/5 is 30% of what number?

Daniel [21]

3/5 of what number =15

5 0

3 years ago

a right pyramid with a square base has a base edge length of 24 feet and slant height of 20 feet what is the height of the pyram

Sphinxa [80]

Let

l-------> the slant height of the right pyramid

b------> the length side of the square base of the right pyramid

h------> the height of the right pyramid

we know that

Applying the Pythagorean Theorem

$l^{2} =h^{2}+(\frac{b}{2})^{2}$

Solve for h

$h^{2}=l^{2}-(\frac{b}{2})^{2}$

in this problem we have

$l=20\ ft\\\frac{b}{2} =\frac{24}{2} =12\ ft$

Substitute in the formula

$h^{2}=20^{2}-12^{2}$

$h^{2}=256$

$h=16\ ft$

therefore

the answer is

The height of the right pyramid is $16\ ft$

7 0

3 years ago

Read 2 more answers

What are the zeros of the polynomial function? f(x)=x3+2x2−x−2 Select each correct answer. A.−3 B. −2 C. −1D. 0 E. 1F. 2 G. 3

LenaWriter [7]

Answer:

B. −2

C. −1

E. 1

Step-by-step explanation:

He have been given a polynomial function $f(x)=x^3+2x^2-x-2$ . We are asked to find the zeros of our given function.

To find the zeros of our given function, we will equate our function with zero and solve for x as:

$x^3+2x^2-x-2=0$

Now, we will factor our equation by grouping method.

$(x^3+2x^2)-(x+2)=0$

$x^2(x+2)-1(x+2)=0$

$(x+2)(x^2-1)=0$

Now, we will use difference of squares $a^b-b^2=(a+b)(a-b)$

$(x+2)(x^2-1^2)=0$

$(x+2)(x+1)(x-1)=0$

Using zero product property, we will get:

$(x+2)=0\text{ or }(x+1)=0\text{ or }(x-1)=0$

$x=-2\text{ or }x=-1\text{ or }x=1$

Since the zeros of our given function are $-2,-1\text{ and }1$ , therefore, options B, C and E are correct choices.

4 0

3 years ago

Joe collects Pokemon cards. He already has 100 and buys a dozen more each week when he goes to the store. Jessica also collects

Tomtit [17]

Answer:

5 weeks

Step-by-step explanation:

To find the answer to this question we have to write an equation for both situation and put them equal to each other.

Let's write an equation for Joe:

12x + 100

Now, for Jessica

6x + 130

Next, put them equal to each other:

12x + 100 = 6x + 130

Solve:

12x + 100 = 6x + 130

6x + 100 = 130

6x = 30

x = 5

Therefore, it will take 5 weeks for Joe and Jessica to have the same amount of cards.

Check:

12(5) + 100 = 6(5) + 130

60 + 100 = 30 + 130

160 = 160

I hope this helps!!

- Kay :)

5 0

3 years ago