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lubasha [3.4K]
3 years ago
11

Which element has the lowest electronegativity value?(1) F (2) Fr (3) Cl (4) Cr

Chemistry
2 answers:
Diano4ka-milaya [45]3 years ago
5 0
Remember, electronegativity is a measure of how strongly an atom bonds to its electrons i.e. the likelihood of an atom to attract an electron.

If you think about it, the less electron shells the atom has, the stronger the electrons will bond to the atom. Furthermore, the greater the atom's atomic mass, the more the electrons will be attracted to it.

Knowing this, we're looking for the element that is farthest to the left and bottom of the periodic table. So Francium (Fr) will be your answer.
Rama09 [41]3 years ago
3 0
Francium has the lowest electronegativity value so the answer is (2) Fr :)))
i hope this be helpful 
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4 years ago
Determine the number of protons and neutrons in plutonium-239 and enter its symbol in the form azx.
Komok [63]
Answer:

number of protons: 94
number of neutrons: 145

  239
       Pu
   94

Explanation:

1) The atomic number, Z, of plutonium is Z = 94, i.e plutonium 94 protons

2) Plutoniun-239 is the isotope with mass number 239.

3) Mass number = number of protons + number of neutrons =>

number of neutrons = mass number - number of protons = 239 - 94 = 145

4) The notation requires that you indicate the symbol of the element with the atomic number (number of protons) and the mass number.

You put the mass number as a superscript at the left side of the symbol and the atomic number as subscript to the left of the symbol.

So, in this case the symbol is Pu, the superscript to the left is 239 and the subscript to the left is 94.

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7 0
3 years ago
I am a metal that has 3 valence electrons and 123 neutrons
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Answer:

The answer is Boron

Explanation:

3 0
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sergiy2304 [10]

Answer:  The balanced equation for the given reaction is

2SO_{2}(g) + O_{2}(g) \rightarrow 2SO_{3}(g).

Explanation:

A chemical equation which contains same number of atoms on both reactant and product side.

For example, SO_{2}(g) + O_{2}(g) \rightarrow SO_{3}(g)

Here, number of atoms on reactant side are as follows.

  • S = 1
  • O = 4

Number of atoms on product side are as follows.

  • S = 1
  • O = 3

To balance this equation, multiply SO_{2} by 2 on reactant side and multiply SO_{3} by 2. Hence, the equation will be re-written as follows.

2SO_{2}(g) + O_{2}(g) \rightarrow 2SO_{3}(g)

Here, number of atoms on reactant side are as follows.

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  • O = 6

Number of atoms on product side are as follows.

  • S = 2
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Now, there are same number of atoms on both reactant and product side. So, this equation is balanced.

Thus, we can conclude that the balanced equation for the given reaction is 2SO_{2}(g) + O_{2}(g) \rightarrow 2SO_{3}(g).

3 0
3 years ago
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Dimas [21]
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6 0
3 years ago
Read 2 more answers
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