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Lady_Fox [76]
2 years ago
8

Calculate the total number of ions in 7.41 g of calcium hydroxide, Ca(OH)2. The molar mass of calcium hydroxide is 74.1 g mol–1.

The Avogadro constant is 6.0 × 1023 mol–1.
A) 6.0 × 1022

B) 1.2 × 1023

C) 1.8 × 1023

D) 3.0 × 1023

please explain your answer!​
Chemistry
1 answer:
blondinia [14]2 years ago
5 0
<h3><u>Answer :-</u></h3>

\sf C) 1.8 \times 10^{23}

<h3><u>Explanation:</u><u>-</u></h3>

\red{ \underline { \boxed{ \sf{Moles\: of \: Ca(OH)_2 = \frac{mass\: of\: Ca(OH)_2}{molar\:mass \: of \: Ca(OH)_2}}}}}

\begin{gathered}\\\implies\quad \sf Moles \:of  \:Ca(OH)_2 = \frac{7.41}{74.1} \\\end{gathered}

\begin{gathered}\\\implies\quad \sf Moles\: of\: Ca(OH)_2 = \frac{1}{10}\\\end{gathered}

\sf Ca(OH)_2 dissociate into ions as-

\green{ \underline { \boxed{ \sf{Ca(OH)_2 \longrightarrow Ca^{2+} + 2OH^{-}}}}}

\leadsto 1 mole of \sf Ca(OH)_2 will dissociate into 1 mole of \sf Ca^{2+} and 2 moles of \sf 2OH^{-}

\leadstoSimilarly, 1\10 mole of \sf Ca(OH)_2 will dissociate into 1\10 mole of \sf Ca^{2+} and 2\10 moles of \sf 2OH^{-}

\\

\maltese Total number of ions = \sf Number\: of \:Ca^{2+} ion +\sf Number\: of \:0H^{-} ion

\begin{gathered}\\\implies\quad \sf \frac{1}{\cancel{10}} \times 6.022 \times \cancel{10^{23}}+ \frac{2}{ \cancel{10}}  \times 6.022 \times  \cancel{10^{23}} \\\end{gathered}

\begin{gathered}\\\implies\quad \sf  6.022 \times 10^{22}+  2\times 6.022 \times 10^{22} \\\end{gathered}

\begin{gathered}\\\implies\quad \sf  6.022 \times 10^{22}+  12.044 \times 10^{22} \\\end{gathered}

\begin{gathered}\\\implies\quad \sf  (6.022+12.044) \times 10^{22}\\\end{gathered}

\begin{gathered}\\\implies\quad \sf  18.066 \times 10^{22}\\\end{gathered}

\begin{gathered}\\\implies\quad \sf  1.8066 \times 10^{23}\\\end{gathered}

\begin{gathered}\\\implies\quad \sf  1.8 \times 10^{23}\quad(1.8066 \approx 1.8)\\\end{gathered}

The total number of ions in 7.41 g of calcium hydroxide, \sf Ca(OH)_2 = 1.8 \times 10^{23}

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