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Gala2k [10]
3 years ago
14

PLEASE HELP ME IM SO STRESSED

Mathematics
1 answer:
lora16 [44]3 years ago
8 0

Answer:

  Q'(1, -4)

  R'(1, -3)

  S'(0, 4)

  T'(0, -5)

Step-by-step explanation:

If A is the X-coordinate of a pre-image point, and B is the X-coordinate of the image, then we want 4 to be the midpoint of those values. That is ...

  (A + B)/2 = 4

  A + B = 8 . . . . . multiply by 2

  B = 8 - A . . . . .  subtract A

So, the reflection over x=4 is the transformation ...

  (x, y) ⇒ (8 -x, y)

The y-value stays the same, and the new x-value is the result of subtracting the x-coordinate from 8.

The given points have two different x-coordinates: 7, and 8. The corresponding image coordinates are 8-7 = 1 and 8-8 = 0.

Your points are ...

  Q'(1, -4)

  R'(1, -3)

  S'(0, 4)

  T'(0, -5)

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▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

Let's solve ~

  • 6x + 33 = 6(x + 6)

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AnnZ [28]

Answer:A

Step-by-step explanation:

Given

F(x)=(x+2)^3-4

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3 years ago
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ad-work [718]

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