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ale4655 [162]
2 years ago
11

Consider U = {x\x is a real number}

Mathematics
1 answer:
zysi [14]2 years ago
3 0

Answer:

The fourth pair of statement is true.

9∈A, and 9∈B.

Step-by-step explanation:

Given that,

U={x|  x is real number}

A={x| x∈ U and x+2>10}

B={x| x∈ U and 2x>10}

  • 5 ∈ A , 5 ∈ B

If 5∈ A, Then it will be satisfies x+2>10 , but 5+2<10.

Similarly, If 5∈ B, Then it will be satisfies 2x>10 , but 2.5=10.

So, 5∉A, and 5∉B.

  • 6 ∈ A , 6 ∈ B

If 6∈ A, Then it will be satisfies x+2>10 , but 6+2<10.

Similarly, If 6∈ B, Then it will be satisfies 2x>10 , and 2.6=12>10.

So, 6∉A, and 6∈B.

  • 8 ∈ A , 8 ∈ B

If 8∈ A, Then it will be satisfies x+2>10 , but 8+2=10.

Similarly, If 8∈ B, Then it will be satisfies 2x>10.  2.8=16>10.

So, 8∉A, and 8∈B.

  • 9 ∈ A , 9 ∈ B

If 9∈ A, Then it will be satisfies x+2>10 , but 9+2=11>10.

Similarly, If 9∈ B, Then it will be satisfies 2x>10.  2.9=18>10.

So, 9∈A, and 9∈B.

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Two triangles can be formed with the given information. Use the Law of Sines to solve the triangles. C = 71°, a = 27, c = 26
guajiro [1.7K]

We have

SinC/ c  = Sin A / a

Sin 71/ 26 = Sin A / 27

Sin A  = 27 Sin 71 /  26  = about .982

So°

Sin-1(.982)  = A  = 79. 08°

Then angle B = 180 - 71 - 79.08 = 29.92°

And b is given by

b/sin29.92  = 26/sin 71

b = 26sin29.92/sin71 =  about 13.72

But A could also be an obtuse angle = 180 - 79.08 =  100.92°

So we have

B = 180 - 71 - 100.92 = 8.08°

And we have

b / sin 8.08  = 26/sin71

b = 26sin8.08/sin 71 = 3.865

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A couple purchased a home and signed a mortgage contract for $900,000 to
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9514 1404 393

Answer:

  • $33,336.83
  • $35,176.68
  • $36,869.23
  • $38,266.75
  • $39,158.08

Step-by-step explanation:

The amortization formula can be used to find the payment value.

  A = P(r/2)/(1 -(1 +r/2)^(2n))

where P is the principal amount at the beginning of the loan period, r is the annual interest rate, n is the number of years remaining on the loan

The value of A in this scenario is the semi-annual payment.

Initially, the interest rate is 0.055 and the number of years remaining is 25.

After the first 5-year period, the interest rate goes up by 12%, so is multiplied by a factor of 1.12 to become 6.16% per year. The same growth factor is applied to the interest rate at the beginning of each 5-year period.

Of course, the number of years remaining is decreased by 5 years at the beginning of the next 5-year period.

__

The Principal remaining at the end of each 5-year period is the starting principal for the next period. It is calculated from ...

  FV = P(1 +r/2)^10 -A((1 +r/2)^10 -1)/(r/2)

Where P is the starting principal, A is the loan payment as calculated above, and r is the annual interest rate.

__

These formulas are built into spreadsheet functions, so the desired set of loan payments can be calculated easily by that technology. The result is attached. In the "# pmts" column is the value used to amortize the loan for the 5-year period. The semiannual payment is calculated as though the loan would be completely paid off in that number of payments, keeping the same interest rate for the duration. Of course, that payment series is interrupted and the loan recalculated at the beginning of the next 5 years.

The half-yearly payments for each 5-year interval are ...

  $33,336.83

  $35,176.68

  $36,869.23

  $38,266.75

  $39,158.08

_____

<em>Additional comment</em>

The values displayed in the spreadsheet are rounded to the values shown. The values used in calculation have 14 or more significant digits. This means the numbers here may vary from those provided by a lending institution. In the real world, the principal and interest values are rounded to cents with each payment, so actual results may vary by a few cents either way.

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