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ale4655 [162]
3 years ago
11

Consider U = {x\x is a real number}

Mathematics
1 answer:
zysi [14]3 years ago
3 0

Answer:

The fourth pair of statement is true.

9∈A, and 9∈B.

Step-by-step explanation:

Given that,

U={x|  x is real number}

A={x| x∈ U and x+2>10}

B={x| x∈ U and 2x>10}

  • 5 ∈ A , 5 ∈ B

If 5∈ A, Then it will be satisfies x+2>10 , but 5+2<10.

Similarly, If 5∈ B, Then it will be satisfies 2x>10 , but 2.5=10.

So, 5∉A, and 5∉B.

  • 6 ∈ A , 6 ∈ B

If 6∈ A, Then it will be satisfies x+2>10 , but 6+2<10.

Similarly, If 6∈ B, Then it will be satisfies 2x>10 , and 2.6=12>10.

So, 6∉A, and 6∈B.

  • 8 ∈ A , 8 ∈ B

If 8∈ A, Then it will be satisfies x+2>10 , but 8+2=10.

Similarly, If 8∈ B, Then it will be satisfies 2x>10.  2.8=16>10.

So, 8∉A, and 8∈B.

  • 9 ∈ A , 9 ∈ B

If 9∈ A, Then it will be satisfies x+2>10 , but 9+2=11>10.

Similarly, If 9∈ B, Then it will be satisfies 2x>10.  2.9=18>10.

So, 9∈A, and 9∈B.

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Answer:

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Step-by-step explanation:

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5 0
3 years ago
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The number of accidents per week at a hazardous intersection varies with mean 2.2 and standard deviation of 1.4. The distributio
posledela

Answer:

Approximate probability that \overline{X} is less than 2 = 0.1515

Step-by-step explanation:

Given -

Mean (\nu ) = 2.2

Standard deviation (\sigma  ) = 1.4

Sample size ( n ) = 52

Let  \overline{X} be the mean of accidents per week at the intersection during one year (52 weeks) .

probability that \overline{X} is less than 2 =

P(\overline{X}< 2)  = P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}< \frac{2 - 2.2 }{\frac{1.4}{\sqrt{52}}})   Putting (Z =\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}})

                 = P(Z< - 1.03)    ( Using Z table )

                 = 0.1515

7 0
3 years ago
I need help with truth tables
Lerok [7]

The complete table of truth value for the composite proposition:

       p           q          ¬ q          p ∨ ¬ q            (p ∨ ¬ q) ⇒ q

       T           T             F              T                           T

       T           F             T              T                           F            

       F           T             F              T                           T

       F           F             T              T                           F                

<h3>How to fill a truth table with composite propositions</h3>

In mathematics, propositions are structures that contains a truth value. There are two truth values in classic logics: True, False. Composite propositions are the result combining simpler propositions and operators. There are the following logic operators and rules:

  1. Negation changes the truth value of the proposition into its opposite.
  2. Disjunction brings out "true" value when at least one of the two propositions is so.
  3. Conjunction brings out "true" value when the two propositions are so.
  4. Conditional form brings out "true" value when both propositions are true or only the consequent is true or both propositions are false.

Now we present the complete table of truth value for the composite proposition:

       p           q          ¬ q          p ∨ ¬ q            (p ∨ ¬ q) ⇒ q

       T           T             F              T                           T

       T           F             T              T                           F            

       F           T             F              T                           T

       F           F             T              T                           F                          

To learn more on truth values: brainly.com/question/6869690

#SPJ1

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Answer:

Taylor is 14.

Step-by-step explanation:

Max is 3. Emma is six years older than Max.

3+6=9

Emma is 9. Taylor is five years older than Emma.

9+5=14

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We can set this up as a proportion.

Since 2 is proportional to 1000, then 4 is proportional to "doctors surveyed".

\frac{2}{4}  =  \frac{1000}{d} where d is the doctors surveyed.

Cross multiply.

2d = 4000
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2000 doctors were surveyed.
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