Answer :
<em>(b) 4d orbitals would be larger in size than 3d orbitals</em>
<em>(e) 4d orbitals would have more nodes than 3d orbitals</em>
Explanation :
As we move away from one orbital to another, the distance between nucleus and orbital increases. So, 4d orbitals would be far to the nucleus than 3d orbitals.
Hence, 4d orbitals would be larger in size than 3d orbitals.
Number of nodes is any orbital is n - 1 where, n is principal quantum number.
So, number of orbital in 4d is 3.
And number of orbital in 3d is 2.
So, options (b) and (e) are correct.
Answer:
Explanation:
This question pertains to resonance in air column. It is the case of closed air column in which fundamental note is formed at a length which is as follows
l = λ / 4 where l is length of tube and λ is wave length.
here l = .26 m
λ = .26 x 4 = 1.04 m
frequency of sound = 330 Hz
velocity of sound = frequency x wave length
= 330 x 1.04
= 343.2 m /s
b )
Next overtone will be produced at 3 times the length
so next length of air column = 3 x 26
= 78 cm
c )
If frequency of sound = 256 Hz
wavelength = velocity / frequency
= 343.2 / 256
= 1.34 m
= 134 cm
length of air column for resonance
= wavelength / 4
134/4
= 33.5 cm
The answer is c and my reason is I have straight As
