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Jlenok [28]
3 years ago
10

Compare the characteristics of 4d orbitals and 3d orbitals and compared the following sentences. Check all that apply

Physics
1 answer:
charle [14.2K]3 years ago
8 0

Answer :

<em>(b) 4d orbitals would be larger in size than 3d orbitals</em>

<em>(e) 4d orbitals would have more nodes than 3d orbitals</em>

Explanation :

As we move away from one orbital to another, the distance between nucleus and orbital increases. So, 4d orbitals would be far to the nucleus than 3d orbitals.

Hence, 4d orbitals would be larger in size than 3d orbitals.

Number of nodes is any orbital is n - 1 where, n is principal quantum number.

So, number of orbital in 4d is 3.

And number of orbital in 3d is 2.

So, options (b) and (e) are correct.

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Substances that prevent or reduce the rate of a chemical reaction are called as inhibitors.

<u>Explanation:</u>

Inhibitors are those substances that either prevent or reduce the rate of a chemical reaction. Ex: Acetanilide slows down the decomposition of hydrogen peroxide solution.  

Inhibitors even reduce the effectiveness of catalysts without hindering their composition. There are primarily two kinds of inhibitors- reversible and irreversible. Where, reversible inhibitors slows the rate of any reaction, irreversible inhibitors completely prevents the unwanted reactions.

Where catalysts are used to increase the rate of a reaction, inhibitors stand as a wall for the unwanted reactions to occur. For example, in case of silver tarnishing, to prevent silver jewellery being tarnished, a thin layer of rhodium is applied on it which works like an inhibitor for formation reaction of silver sulphides (the tarnish).

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What is the function of the brain?
erastovalidia [21]

Answer:

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7 0
3 years ago
The heater element of a particular 120-V toaster is a 8.9-m length of nichrome wire, whose diameter is 0.86 mm. The resistivity
AleksAgata [21]

Answer:

Power, P = 722.96 watts

Explanation:

It is given that,

Voltage, V = 120 V

Length of nichrome wire, l = 8.9 m

Diameter of wire, d = 0.86 mm

Radius of wire, r = 0.43 mm = 0.00043 m

Resistivity of wire, \rho=1.3\times 10^{-6}\ \Omega-m

We need to find the power drawn by this heater. Power is given by :

P=\dfrac{V^2}{R}

And, R=\rho\dfrac{l}{A}

P=\dfrac{V^2\times A}{\rho\times l}

P=\dfrac{120^2\times \pi (0.00043)^2}{1.3\times 10^{-6}\times 8.9}

P = 722.96 watts

So, the power drawn by this heater element is 722.96 watts. Hence, this is the required solution.    

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