Answer:
Final temperature, ![T_f=21.85^{\circ}](https://tex.z-dn.net/?f=T_f%3D21.85%5E%7B%5Ccirc%7D)
Explanation:
Given that,
Mass of silver ring, m = 4 g
Initial temperature, ![T_i=41^{\circ}C](https://tex.z-dn.net/?f=T_i%3D41%5E%7B%5Ccirc%7DC)
Heat released, Q = -18 J (as heat is released)
Specific heat capacity of silver, ![c=0.235\ J/g\ C](https://tex.z-dn.net/?f=c%3D0.235%5C%20J%2Fg%5C%20C)
To find,
Final temperature
Solution,
The expression for the specific heat is given by :
![Q=mc\Delta T](https://tex.z-dn.net/?f=Q%3Dmc%5CDelta%20T)
![Q=mc(T_f-T_i)](https://tex.z-dn.net/?f=Q%3Dmc%28T_f-T_i%29)
![T_f=\dfrac{-Q}{mc}+T_i](https://tex.z-dn.net/?f=T_f%3D%5Cdfrac%7B-Q%7D%7Bmc%7D%2BT_i)
![T_f=\dfrac{-18}{4\times 0.235}+41](https://tex.z-dn.net/?f=T_f%3D%5Cdfrac%7B-18%7D%7B4%5Ctimes%200.235%7D%2B41)
![T_f=21.85^{\circ}](https://tex.z-dn.net/?f=T_f%3D21.85%5E%7B%5Ccirc%7D)
So, the final temperature of silver is 21.85 degrees Celsius.
On sources it says it would just be the super giant star
According to Newton, an object will only accelerate if there is a net or unbalanced forceacting upon it. The presence of an unbalanced force will accelerate an object - changing its speed, its direction, or both its speed and direction.
For the first hour, the slope is zero.
After that, the slope is -2 miles per hour.
What object do you need to match