For example, in the composition of(f g)(x) = f(g(x)), we need to replace each x found in f(x), the outside function, with g(x), the inside function. Step 3: Simplify the answer. Examples – Now let's use the steps shown above to work through some examples. Example 1: If f(x) = –4x + 9 and g(x) = 2x – 7, find(f g)(x).
Answer:
c=11/36
Step-by-step explanation:
i dont know if that what you want + what is the source of you question?
Answer:
Equation of parabola: 8*(y - 2) = (x - 3)^2
or
y = (1/8)*(x - 3)^2 + 2
Step-by-step explanation:
focus at (3,4) and its directrix y = 0.
Focus equation: (h, k + c) = (3, 4)
Directrix equation y = k - c = 0
so h = 3, k + c = 4, k - c = 0
Solve the system : k + c = 4 and k - c = 0
add the equations together: k + c + k - c = 4 + 0
2k = 4
k = 2
so k + c = 4, 2 + c = 4, c = 2
4c (y - k) = (x - h)^2
4*2 *(y - 2) = (x - 3)^2
8*(y - 2) = (x - 3)^2
Answer:
Step-by-step explanation:
In this question, you would solve the for f(x) by plugging in the given value to x.
Solve:
Distribute the exponent to the numerator and denominator.
Simplify.
Use the 
rule for the numerator:
Your final answer would be
Answer:
a) P(X ≤ 4) = 0.9
b) P(X>7) = 0
c) P(X ≤ 5) = 0.9
d) P(X>4) = 0.1
e) P(X≤2)= 0.7
Step-by-step explanation:
Hello!
Given the distribution of cumulative probability
0 for X < 1
F(x) 0.7 for 1 ≤ X < 4
0.9 for 4 ≤ X < 7
1 for 7 ≤ X
To determine each of the asked probabilities you have to select the probability corresponding to the defined intervals for X:
a) P(X ≤ 4) = 0.9
This value of X is included the interval "4 ≤ X < 7" so the corresponding probability is 0.9
b) P(X>7) = 0
This is equal to the expression:
1 - P(X≤7)
This expression is included in the last interval so the probability is 1
1 - 1 = 0
c) P(X ≤ 5) = 0.9
5 is included in the third interval "4 ≤ X < 7" so the corresponding probability is 0.9
d) P(X>4) = 0.1
P(X>4) = 1 - P(X≤4)
P(X≤4) is in the interval of definition "4 ≤ X < 7" so the corresponding probability is 0.9
1 - 0.9 = 0.1
e) P(X≤2)= 0.7
The value X=2 is included in the second interval "for 1 ≤ X < 4", so the probability is 0.7
I hope it helps!
