Find all the zeros of the polynomial, and arrange the zeros in increasing order. ...
Plot those numbers on the number line as open or closed points based upon the original inequality symbol.
Choose a test value in each interval to see if the interval satisfies the inequality or not.
So add all the numbers together (20 + 22 + 28 + 35 + 47 + 90) and you'll get 242. Then you take the number and divide it by the numbers in your set (you have 6 numbers so you'll divide by 6) 242/6. The answer would be 40.3333333 (repeating decimal). I hope this helps!
Answer:
x > -1
Step-by-step explanation:
Simplify the inequality using the distributive property (multiply the term outside the bracket with each number inside the bracket). Then, isolate 'x' by performing the reverse operations for every number that's on the same side as 'x'. (Reverse operations 'cancel out' a number.)
18 < -3(4x - 2) Expand this to simplify
18 < (-3)(4x) - (-3)(2) Multiply -3 with 4x and -2
18 < -12x + 6 Start isolating 'x'
18 - 6 < -12x + 6 - 6 Subtract 6 from both sides
18 - 6 < -12x '+ 6' is cancelled out on the right side
12 < -12x Subtracted 6 from 18 on the left side
12/-12 < -12x/-12 Divide both sides by -12
12/-12 < x 'x' is isolated. Simplify left side
-1 < x Answer
x > -1 Standard formatting puts variable on the left side
The slope is 3 and the y-intercept is (0, 9.4)
Explanation:
When the inequality symbol is replaced by an equal sign, the resulting linear equation is the boundary of the solution space of the inequality. Whether that boundary is included in the solution region or not depends on the inequality symbol.
The boundary line is included if the symbol includes the "or equal to" condition (≤ or ≥). An included boundary line is graphed as a solid line.
When the inequality symbol does not include the "or equal to" condition (< or >), the boundary line is not included in the solution space, and it is graphed as a dashed line.
Once the boundary line is graphed, the half-plane that makes up the solution space is shaded. The shaded half-plane will be to the right or above the boundary line if the inequality can be structured to be of one of these forms:
- x > ... or x ≥ ... ⇒ shading is to the right of the boundary
- y > ... or y ≥ ... ⇒ shading is above the boundary
Otherwise, the shaded solution space will be below or to the left of the boundary line.
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Just as a system of linear equations may have no solution, so that may be the case for inequalities. If the boundary lines are parallel and the solution spaces do not overlap, then there is no solution.
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The attached graph shows an example of graphed inequalities. The solutions for this system are in the doubly-shaded area to the left of the point where the lines intersect. We have purposely shown both kinds of inequalities (one "or equal to" and one not) with shading both above and below the boundary lines.