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ch4aika [34]
3 years ago
9

Beula has a collection of video games. There are 12 games in the collection, and 2/4 of them are console games. Beula decides to

double the amount of console games. 1. How many console games are in the collection now? 2. What fraction the games are console games now?
Mathematics
1 answer:
barxatty [35]3 years ago
4 0

Answer:

12 console games

Step-by-step explanation:

if 2/4 are console games when you have 12, that means 6/12 are console games so to double the amount, add 6. 12+6=18.

12 out of the 18 are now console games making console games 6/9 (2/3 simplified) of the game collection.

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Delicious77 [7]

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\bf \displaystyle\int~\cfrac{~~\begin{matrix} sin(4x-1) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ }{u^2}\cdot \cfrac{du}{-4~~\begin{matrix} sin(4x-1) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\implies -\cfrac{1}{4}\int\cfrac{1}{u^2}du\implies -\cfrac{1}{4}\int u^{-2}du \\\\\\ -\cfrac{1}{4}\cdot \cfrac{u^{-2+1}}{-1}\implies \cfrac{1}{4}\cdot u^{-1}\implies \cfrac{1}{4u}\implies \cfrac{1}{4cos(4x+1)}+C

5 0
3 years ago
Aidan has 20 ft of fence with which to build a rectangular dog run. What is the maximum area he can enclose? Enter your answer i
irina1246 [14]
<h2>Maximum area is 25 m²</h2>

Explanation:

Let L be the length and W be the width.

Aidan has 20 ft of fence with which to build a rectangular dog run.

         Fencing = 2L + 2W  = 20 ft

                     L + W = 10

                      W = 10 - L

We need to find what is the largest area that can be enclosed.

     Area = Length x Width

      A = LW

       A = L x (10-L) = 10 L - L²

For maximum area differential is zero

So we have

      dA = 0

      10 - 2 L = 0

        L = 5 m

      W = 10 - 5 = 5 m

Area = 5 x 5 = 25 m²

Maximum area is 25 m²

7 0
3 years ago
Is 97 an irrational number?
user100 [1]

Answer:

<em>No </em><em>9</em><em>7</em><em> </em><em>is </em><em>not </em><em>an </em><em>irrational </em><em>number </em>

Step-by-step explanation:

Be happy

7 0
2 years ago
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An identification code is to consist of 2 letters followed by 3 digits. how many different codes are possible if repetition is p
Vedmedyk [2.9K]
I like the 'question mark' at the end:

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Now, this was for LLDDD (Letter Letter Digit Digit Digit)

It seems this is the order they want. Other wise, one should multiply by all the combinations in the order: LDLDD, DLLDD, etc ... (10 combinations), but again it seems they want this LLDDD

So 676000



5 0
3 years ago
Please help immediately
mote1985 [20]

Answer:

There are 12 possible outcomes.

Step-by-step explanation:

This question represents combined independent events of probability.  Independent events are not affected by previous events.  So, your probability is the same with each flip of the coin or roll of the die.  So, you just have to look at the total number of outcomes for each and multiply them.  Since there are only two sides to a coin, there are only two total outcomes.  Since there are six sides to a die, there are only six total outcomes.  2 x 6 = 12 total outcomes.  

4 0
2 years ago
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