Answer:

Step-by-step explanation:
Given <u>v</u> = < - 5, 9 > then the magnitude is
| <u>v</u> | =
=
= 
Answer:
30m
Step-by-step explanation:
<em>Since we are not told what to look for, we can find the maximum height reached by the rocket</em>
Given the rocket's flight approximately modeled by the equation
h(t) = - 12t ^ 2 + 36t + 3
At maximum height dh/dt = 0
dh/dt = --24t + 36
0 = -24t + 36
24t = 36
t= 36/24
t = 1.5s
Get the max height
h(1.5) = - 12 (1.5)^ 2 + 36(1.5) + 3
h(1.5) = - 12(2.25) + 54 + 3
h(1.5) = -27 + 57
h(1.5) = 30m
Hence the maximum height reached by the rocket is 30m
<u>Solution</u><u> </u><u>:</u><u>-</u>
Here, we have been given that lines f and g are parallel. Thus, the angle measuring 135° and ∠2 are vertically opposite angles.
And we know that vertically opposite angles measure same. Thus,
∠2 = 135°
And,
∠2 + ∠6 = 180° ( Co - interior angles sum up to 180° )
135° + ∠6 = 180°
∠6 = 180° - 135°
∠6 = 45°
Now,
we see that ∠6 and ∠5 are making a linear pair of angles, and we know that angles in a linear pair measure 180° Thus,
∠5 + 45° = 180°
∠5 = 180° - 45°
∠5 = 135°
Thus, the value of angle 5 is 135°
Hope that helps. :)