Two very large parallel sheets are 5.00 cm apart. Sheet A carries a uniform surface charge density of -8.10 μC/m2 , and sheet B,
which is to the right of A, carries a uniform charge of -13.0 μC/m2 . Assume the sheets are large enough to be treated as infinite.Part AFind the magnitude of the net electric field these sheets produce at a point 4.00 cm to the right of sheet A.Part BFind the direction of the net electric field these sheets produce at a point 4.00 cm to the right of sheet A.Part CFind the magnitude of the net electric field these sheets produce at a point 4.00 cm to the left of sheet A.Part DFind the direction of the net electric field these sheets produce at a point 4.00 cm to the left of sheet A.Part EFind the magnitude of the net electric field these sheets produce at a point 4.00 cm to the right of sheet B.
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According to Newton's second law, the force applied to an object is equal to the product between the mass of the object and its acceleration:
where F is the magnitude of the force, m is the mass of the object and a its acceleration.
In this problem, the object is the insect, with mass
. The acceleration of the insect is 
, therefore we can calculate the force exerted by the car on the insect:
How do we find the force exerted by the insect on the car?
According to Newton's third law (known as action-reaction law), when an object A exerts a force on an object B, object B also exerts a force equal and opposite on object A. Therefore, the force exerted by the insect on the car is equal to the force exerted by the car on the object, so it is 0.01 N.
where F is the magnitude of the force, m is the mass of the object and a its acceleration.
In this problem, the object is the insect, with mass
How do we find the force exerted by the insect on the car?
According to Newton's third law (known as action-reaction law), when an object A exerts a force on an object B, object B also exerts a force equal and opposite on object A. Therefore, the force exerted by the insect on the car is equal to the force exerted by the car on the object, so it is 0.01 N.