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3 years ago

6

a falling skydiver slows from a speed of 52 m/s to 8 m/s in 0.8 sec as the parachute opens. what is the diver's acceleration and

the displacement ?

1 answer:

Cloud [144]3 years ago

8 0

I found the answers here. Hope this helps you! https://1.cdn.edl.io/sJTle6yxt3qVq7jHfdHRZJ3Xogj7ps6swBO9umNcZ6PO3SMN.docx

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I need help answering 30A and B. Help a guy out?

dmitriy555 [2]

Uh so I'm no master at this subject, but all stuffs accelerate at 9.8 m/s squared. So you multiply the 9.8 and the 0.20 it's given for reasons unknown other than that's what I see in my notes... and that gives you 1.96 m/s squared.

As for B, I have no idea. I think you may multiply the 1.96 by 4. Tell me your thoughts and maybe we can work it out together

5 0

3 years ago

Ph11_UnitPacket2019

frozen [14]

Let's see

Use snells law

$\\ \rm\Rrightarrow \dfrac{n_1}{n_2}=\dfrac{sini}{sinr}$

$\\ \rm\Rrightarrow \mu=\dfrac{sin30}{sin19.9}$

$\\ \rm\Rrightarrow \mu=0.5/0.34$

$\\ \rm\Rrightarrow \mu=1.47$

It may be glass

3 0

2 years ago

Five identical quintuplets leave earth when they reach the age of 21, in the year 2121. Each quintuplet goes on a spaceship jour

Elena-2011 [213]

Answer:

Explanation:

This is a problem based on time dilation , a theory given by Albert Einstein .

The formula of time dilation is as follows .

t₁ = $\frac{t}{\sqrt{1-\frac{v^2}{c^2} } }$

t is time measured on the earth and t₁ is time measured by man on ship .

A ) Given t = 20 years , t₁ = ? v = .4c

$\frac{20}{\sqrt{1-\frac{.16c^2}{c^2} } }$

=1.09 x 20

t₁= 21.82 years

B ) Given t = 5 years , t₁ = ? v = .2c

$\frac{5}{\sqrt{1-\frac{.04c^2}{c^2} } }$

=1.02 x 5

t₁= 5.1 years

C ) Given t = 10 years , t₁ = ? v = .8c

$\frac{10}{\sqrt{1-\frac{.64c^2}{c^2} } }$

=1.67 x 10

t₁= 16.7 years

D ) Given t = 10 years , t₁ = ? v = .4c

$\frac{10}{\sqrt{1-\frac{.16c^2}{c^2} } }$

=1.09 x 10

t₁= 10.9 years

E ) Given t = 20 years , t₁ = ? v = .8c

$\frac{20}{\sqrt{1-\frac{.64c^2}{c^2} } }$

=1.67 x 20

t₁= 33.4 years

7 0

2 years ago

How much work (in J) is done against the gravitational force on a 3.9 kg briefcase when it is carried from the ground floor to t

katrin2010 [14]

Answer:

W = 14523.6 J

Explanation:

Given,

Mass = 3.9 Kg

Vertical height , h = 380 m

Work done against gravitational force

W = m g h

g is acceleration due to gravity

W = 3.9 x 9.8 x 380

W = 14523.6 J

Hence, the work done by the gravitational force is equal to W = 14523.6 J

3 0

3 years ago

Need help 8th grade work

Alisiya [41]

1) Ecology

2) Food Web

3) Trophic Level

4) Producer

5) Autotroph

6) Consumer

7) Heterotroph

8) Decomposer

Hope tHis Helps ._.

6 0

3 years ago

Read 2 more answers