Which force controls the size of an atomic nucleus?

Why do we use a spaceship in outer space, far from other objects, to illustrate the principle that an object that does not inter

HACTEHA [7]

Complete Question: Why do we use a spaceship in outer space, far from other objects, to illustrate the principle that an object that does not interact with anything travels at constant speed in a straight line (Newton's first law)? Why not a car or a train? (Select all that apply.)

(1) A car or train touches other objects, and interacts with them.

(2) A car or train can't travel fast enough.

(3) The spaceship has negligible interactions with other objects.

(4) A car or train interacts gravitationally with the Earth.

(5) A spaceship can never experience a gravitational force.

Answer:

(1), (3), (4), (5)

Explanation:

In order to be able to move in a straight line at constant speed forever, as stated by Newton's first law, the object can't be subject to any external net force that can change its momentum.

1) A car, or train, interacts with other objects (the air, the road surface, or the rails, for instance) which means that sooner or later, it will come to an stop, so, for this reason, is not a good fit for that purpose.

3) As it is assumed that the spaceship has negligible interactions with another objects, it will continue moving in a straight line at a constant speed, forever, so it's a good fit to explain Newton's first law.

4) As the train, or a car, or any earthling object, is subject to the gravitational attractive force from Earth, it is not possible for them to move along a straight line at a constant speed forever, as stated by Newton's first law, so a train or a car definitely aren't a good fit in order to explain it.

5) Even though a spaceship can actually experiment a gravitational force from any mass close enough to it, as stated by Newton's Universal Law of Gravitation, in order to simplify things, in this case, usually we neglect any of them.

3 0

4 years ago

What are the STEPS to using a triple beam balance

Gwar [14]

A good diet. and exersise is the answer

8 0

4 years ago

An alternative to CFL bulbs and incandescent bulbs are light-emitting diode (LED) bulbs. A 16-W LED bulb can replace a 100-W inc

Yanka [14]

Answer:

LED bulb = 0.145 A

Incandescent bulb = 0.909 A

CFL bulb = 0.218 A

Explanation:

Given:

Power rating of LED bulb (P₁) = 16 W

Power rating of incandescent bulb (P₂) = 100 W

Power rating of CFL bulb (P₃) = 24 W

Terminal voltage across the circuit (V) = 110 V

We know that, power is related to terminal voltage and current drawn as:

$P=VI$

Express this in terms of 'I'. This gives,

$I=\frac{P}{V}$

Now, calculate the current drawn in each bulb using their respective values.

For LED bulb, $P_1=16\ W, V=110\ V$

So, current drawn is given as:

$I_1=\frac{16\ W}{110\ V}=0.145\ A$

For incandescent bulb, $P_2=100\ W, V=110\ V$

So, current drawn is given as:

$I_2=\frac{100\ W}{110\ V}=0.909\ A$

For CFL bulb, $P_3=24\ W, V=110\ V$

So, current drawn is given as:

$I_3=\frac{24\ W}{110\ V}=0.218\ A$

Therefore, the currents drawn through LED bulb, incandescent bulb and CFL bulb are 0.145 A, 0.909 A and 0.218 A respectively.

5 0

4 years ago

You are pulling a sled using a horizontal rèpe, as shown in the diagram. The rope pulls the sled. exerting a force of 50 N to th

Luden [163]

Answer:

Explanation:

From your other post, the complete question is:

"You are pulling a sled using a horizontal rèpe, as shown in the diagram. The rope pulls the sled. exerting a force of 50 N to the right. The snow exerts a friction force of 30 N on the sled to the left. The mass of the sled is 50 kg.

Find the sum of the force on the sled.

Determine the acceleration of the sled .

If the sled has an initial velocity 2m/s to the right, how fast will it be traveling after 5 seconds?

"

Given the rope exerting a force of 50 N to the right and the snow exerts a friction force of 30 N to the left, the sum of forces

= 50 - 30

= 20N to the right

The mass of sled is 50 kg and force = mass * acceleration.

Acceleration = Force / mass

= 20 / 50 = 0.4 m/s^2 to the right

If the sled has an initial velocity 2m/s to the right, after 5 seconds it will be traveling at initial velocity + acceleration * time

= 2 + 0.4*5

= 4 m/s to the right

3 0

3 years ago

Read 2 more answers

benzene c6h6 and toluene c6h5ch3 for ideal solutions. at 35c the vapor pressure of benzene is 160 torr and that of toluene is 50

LuckyWell [14K]

Answer:

mole fraction of toluene 0.53

Explanation:

given data:

vapor pressure of benzene = 160 torr

vapor pressure of toluene = 50 torr

mole of benzene = 3.8 mol

mole of toluene = 5.7 mol

calculate total pressure

here total pressure = mole fraction of toluene x vapour pressure of toluene + mole fraction of benzene x vapor pressure of benzene

mole fraction of toluene $= \frac{5.7}{5.7+3.8}$

mole fraction of Benzene $= \frac{3.8}{5.7+3.8}$

$= \frac{5.7}{( 5.7 + 3.8 )}*50 + \frac{3.8}{5.7 + 3.8}*160$

= 94 torr

we have mole fraction of toluene in vapor phase =\frac{50}{94} =

= 0.53 (ans)

6 0

3 years ago