All categories

3 years ago

Which set of side measurements could be a triangle? Select two answers.

Mathematics

1 answer:

ipn [44]3 years ago

5 0

I think the answer is c) I could be wrong tho. No promises

You might be interested in

Find the total surface area of the cube

prisoha [69]

Each square is 2.2*2.2= 4.84 sqin
6 squares: 4.84*6= 29.04
hope this helps

6 0

2 years ago

3 times a number is 54 less than the square of that number

Natasha2012 [34]

Answer:

-6

Step-by-step explanation:

3n = n² - 54

n² - 3n - 54 = 0

n² - 9n + 6n - 54 = 0

n(n - 9) + 6(n - 9) = 0

(n - 9)(n + 6) = 0

n = 9 , -6

hope this helps

8 0

2 years ago

Read 2 more answers

Write the equation for the following relation. Include all of your work in your final answer. \[R=\left\{(x,y):(4,5),\ (8,7),\ (

Alik [6]

Answer:12.9

Step-by-step explanation:

7 0

2 years ago

Solve each of the following for the indicated variable.a. 9 − 6 = 54 for yb. = 2 + 2 for l

marta [7]

Answer:

$\begin{gathered} y=\frac{9}{6}x-9 \\ l=\frac{P}{2}-w \end{gathered}$

Step-by-step explanation:

To solve the following equations, we need to isolate the variable asked using inverse operations to solve equations.

Remember that addition and subtraction are inverse operations, as multiplication and division.

Therefore,

$\begin{gathered} a\text{. Solve for y} \\ 6y=9x-54 \\ y=\frac{9}{6}x-\frac{54}{6} \\ y=\frac{9}{6}x-9 \end{gathered}$ $\begin{gathered} b\text{. Solve for l} \\ P=2l+2w \\ 2l=P-2w \\ l=\frac{P}{2}-\frac{2}{2}w \\ l=\frac{P}{2}-w \end{gathered}$

4 0

1 year ago

Estimate the limit A B C D

Lera25 [3.4K]

Answer:

C. $\lim_{x\rightarrow f(x)=2$

Step-by-step explanation:

Given problem is $\lim_{x\rightarrow \frac{\pi}{4}}\frac{tan(x)-1}{x-\frac{\pi}{4}}$ .

Now we need to evaluate the given limit.

If we plug $\x=\frac{\pi}{4}$ , into given problem then we will get 0/0 form which is an indeterminate form so we can apply L Hospitals rule

take derivative of numerator and denominator

$\lim_{x\rightarrow \frac{\pi}{4}}\frac{tan(x)-1}{x-\frac{\pi}{4}}$

$=\lim_{x\rightarrow \frac{\pi}{4}}\frac{sec^2(x)-0}{1-0}$

$=\frac{sec^2(\frac{\pi}{4})-0}{1-0}$

$=\frac{(\sqrt{2})^2}{1}$

$=\frac{2}{1}$

Hence choice C is correct.

5 0

3 years ago