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AlexFokin [52]
3 years ago
6

lavatory tests show that the lives of light bulbs are normally distributed with a mean of 750 hours and a stoandard devotion of

75 hours. Find the porbability that a randomly selected light bulb will last between 900 and 975 yours
Mathematics
1 answer:
maria [59]3 years ago
5 0

Answer:h

Step-by-step explanation:6

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If y = -10 -x, find y when x = -2​
arlik [135]

Answer:

y = -8

Step-by-step explanation:

y = -10 - x

y = -10 - (-2)

y = -10 + 2

y = -8

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Durind the summer, Ms. Stevenson likes to swim. Her goal next summer is to swim1,456 laps. If she swims 28 laps a day, how many
WINSTONCH [101]

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52

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6 0
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Apr 17, 1:42:09 AM
SVEN [57.7K]

Answer:

(-1, 5)

Step-by-step explanation:

3 [x + y = 4]

  3x + 3y = 12

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3 0
2 years ago
An economy pack of highlighters contains 12 yellow, 6 blue, 4 green, and 3 orange highlighters. An experiment consists of random
Serhud [2]

Answer:

The probability of choosing a blue or yellow highlighter when one yellow highlighter is picked is 17/25.

Step-by-step explanation:

Here, according to the question:

Total number of yellow highlighters  = 12

Total number of blue  highlighters  = 6

Total number of green highlighters  = 4

Total number of orange  highlighters  = 3

So, the total number of highlighters  =  12 + 6 + 4 + 3  = 25

Let E1 : Event of selecting a yellow highlighter.

P(E1)  = \frac{\textrm{Total number of yellow highlighters}}{\textrm{Total Highlighters}}  = \frac{12}{25}

Let E2 : Event of selecting blue or yellow highlighter ONCE yellow highlighter is selected.

So, the total yellow highlighters left after selecting one = 12 -1  = 11

Also, the number of blue highlighter  =  6

So, the TOTAL FAVORABLE options to E2 = 6+ 11 = 17

P(E2)  =

\frac{\textrm{Total number of yellow  + Blue   highlighters}}{\textrm{Total Highlighters}} = \frac{17}{25}

Hence, the probability that a blue or yellow highlighter is selected given that a yellow highlighter is selected is 17/25.

7 0
3 years ago
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