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4 years ago

You get home on a cold winter day and turn on the hea

Physics

1 answer:

Allushta [10]4 years ago

4 0

The heat transferred by room heater to the room is an example of convection heat flow.

Answer: Option D

<u>Explanation:</u>

It is known that heat or thermal energy generally flows from high temperature to low temperature. Heat can be transferred in four ways. They are conduction, convection, radiation and electro-magnetic waves. So, in the present case, if we are turning on the heater highers the temperature of the room, we need to use room heaters. And generally room heaters utilize convection technology to flow the heat energy.

In convection mode of heat flow, the heat energy generated at the source i.e., in the coils of the room heater is made to flow away from the source using the fan or radiator kind of thing. So, this process of transfer of heat energy from the point of generation by making the heat flow or rise is termed as convection. And thus, convection is the best example which is used in room heater.

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Is freezing outside on a cold day conduction convection or radiation?

harina [27]

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4 years ago

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I am Lyosha [343]

A bonds with elements from b

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You drop a rock off of a cliff at exactly the edge after 25 seconds exactly you hear a splash your physics friend tells you the

Reptile [31]

The speed of sound is 340.29 meters per second.

Knowing that, we can calculate how high this cliff is by 340.29 * .4

The cliff is 340.29 * .4 = 136.12 meters

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4 years ago

Based on the simple blackbody radiation model described in class, answer the following question. The planets Mars and Venus have

Lera25 [3.4K]

Answer:

The extent of greenhouse effect on mars is $G_m = 87 K$

Explanation:

From the question we are told that

The albedo value of Mars is $A_1 = 0.15$

The albedo value of Mars is $A_2 = 0.15$

The surface temperature of Mars is $T_1 = 220 K$

The surface temperature of Venus is $T_2 = 700 K$

The distance of Mars from the sun is $d_m = 2.28*10^8 \ km = 2.28*10^8* 1000 = 2.28*10^{11} \ m$

The distance of Venus from sun is $d_v = 1.08 *10^{8} \ km = 1.08 *10^{8} * 1000 = 1.08 *10^{11} \ m$

The radius of the sun is $R = 7*10^{8} \ m$

The energy flux is $E = 6.28 * 10^{7} W/m^2$

The solar constant for Mars is mathematically represented as

$T = [\frac{E R^2 (1- A_1)}{\sigma d_m} ]$

Where $\sigma$ is the Stefan's constant with a value $\sigma = 5.6*10^{-8} \ Wm^{-2} K^{-4}$

So substituting values

$T = \frac{6.28 *10^{7} * (7*10^8)^2 * (1-0.15)}{(5.67 *10^{-8}) * (2.28 *10^{11})^2)}$

$T = 307K$

So the greenhouse effect on Mars is

$G_m = T - T_1$

$G_m = 307 - 220$

$G_m = 87 K$

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4 years ago

How much energy must be added to a 2-kg piece of glass with a specific heat

MAXImum [283]

Answer:

51520J

Explanation:

The energy added to the piece of glass is also called heat needed to increase its temperature from 10°C to 50°C and it depends on the mass, specific heat capacity and the change in temperature.

Q=m.c.ΔT

Q=(2kg).(644J/(kg°C)).((50°C)-(10°C))

Q=51520J

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4 years ago