1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Rus_ich [418]
3 years ago
5

If the astronaut throws the tool with a force of 16.0 n , what is the magnitude of the acceleration a of the astronaut during th

e throw? assume that the total mass of the astronaut after she throws the tool is 80.0 kg . express your answer in meters per second squared.
Physics
2 answers:
Drupady [299]3 years ago
7 0

The magnitude of the acceleration of the astronaut : <u>0.2 m/s²</u>

<h3>Further explanation </h3>

Newton's 2nd law explains that the acceleration produced by the resultant force on an object is proportional and in line with the resultant force and inversely proportional to the mass of the object

∑F = m. a

\large {\boxed {\bold {a = \frac {\sum F} {m}}}

F = force, N

m = mass = kg

a = acceleration due to gravity, m / s²

the astronaut throws the tool with a force of 16.0 N ⇒  F = 16 N

the total mass of the astronaut after she throws the tool is 80.0 kg

 ⇒ m = 80 kg

magnitude of the acceleration of the astronaut during the throw

\rm a=\dfrac{F}{m}\\\\a=\dfrac{16\:N}{80\:kg}\\\\a=\boxed{\bold{0.2\:\dfrac{m}{s^2}}}

<h3>Learn more </h3>

law of motion  

brainly.com/question/75210  

displacement of A skateboarder

brainly.com/question/1581159

The distance of the elevator  

brainly.com/question/8729508  

Maksim231197 [3]3 years ago
4 0

From Newton’s second law of motion, the value of the force is calculated by multiplying the mass and the acceleration as,

<span>                                             F = mass   x acceleration</span>

If we substitute the known values into the equation,

<span>                                             16 N = 80 kg x acceleration</span>

<span>                                               Acceleration = 0.2 m/s<span>2</span></span>

You might be interested in
An object of mass 2.0 kg is attached to the top of a vertical spring that is anchored to the floor. The unstressed length of the
poizon [28]

Answer:

The value is A  =  0.014 \  m

Explanation:

From the question we are told that

    The mass of the object is  m  =  2.0 \  kg

    The unstressed length of the string is  l  =  0.08 \  m

    The length of the spring when it is  at equilibrium is  l_e = 5.9 \  cm  =  0.059 \  m

      The initial speed (maximum speed)of the spring when given a downward blow v  =  0.30 \  m/s

Generally the maximum speed  of the spring  is mathematically represented as

           u =  A *  w

Here A is maximum height above the floor (i.e the maximum amplitude)

            and w is the angular frequency which is mathematically represented as

       w = \sqrt{\frac{k}{m} }

So

        u =  A *   \sqrt{\frac{k}{m} }

=>      A  =  u *   \sqrt{\frac{m}{k} }

Gnerally the length of the compression(Here an assumption that the spring was compressed to the ground by the hammer is made) by the hammer is mathematically represented as

           b  =  l -l_e

=>         b  = 0.08 - 0.05 9

=>         b  = 0.021 \  m

Generally at equilibrium position the net force acting on the spring is  

            k *  b  -  mg  =  0

=>         k *  0.021   -   2 * 9.8  =  0

=>        k =  933 \  N/m

So

            A  =  0.30  *   \sqrt{\frac{2}{933} }

=>          A  =  0.014 \  m

8 0
3 years ago
A group of students prepare for a robotic competition and build a robot that can launch large spheres of mass M in the horizonta
jeyben [28]

Answer:

V_0

Explanation:

Given that, the range covered by the sphere, M, when released by the robot from the height, H, with the horizontal speed V_0 is D as shown in the figure.

The initial velocity in the vertical direction is 0.

Let g be the acceleration due to gravity, which always acts vertically downwards, so, it will not change the horizontal direction of the speed, i.e. V_0 will remain constant throughout the projectile motion.

So, if the time of flight is t, then

D=V_0t\; \cdots (i)

Now, from the equation of motion

s=ut+\frac 1 2 at^2\;\cdots (ii)

Where s is the displacement is the direction of force, u is the initial velocity, a is the constant acceleration and t is time.

Here, s= -H, u=0, and a=-g (negative sign is for taking the sigh convention positive in +y direction as shown in the figure.)

So, from equation (ii),

-H=0\times t +\frac 1 2 (-g)t^2

\Rightarrow H=\frac 1 2 gt^2

\Rightarrow t=\sqrt {\frac {2H}{g}}\;\cdots (iii)

Similarly, for the launched height 2H, the new time of flight, t', is

t'=\sqrt {\frac {4H}{g}}

From equation (iii), we have

\Rightarrow t'=\sqrt 2 t\;\cdots (iv)

Now, the spheres may be launched at speed V_0 or 2V_0.

Let, the distance covered in the x-direction be D_1 for V_0 and D_2 for 2V_0, we have

D_1=V_0t'

D_1=V_0\times \sqrt 2 t [from equation (iv)]

\Rightarrow D_1=\sqrt 2 D [from equation (i)]

\Rightarrow D_1=1.41 D (approximately)

This is in the 3 points range as given in the figure.

Similarly, D_2=2V_0t'

D_2=2V_0\times \sqrt 2 t [from equation (iv)]

\Rightarrow D_2=2\sqrt 2 D [from equation (i)]

\Rightarrow D_2=2.82 D (approximately)

This is out of range, so there is no point for 2V_0.

Hence, students must choose the speed V_0 to launch the sphere to get the maximum number of points.

7 0
3 years ago
What is the internal energy of 2.00 mol of diatomic hydrogen gas (H2) at 35°C?
djyliett [7]
As you mentioned, we will use <span>Equipartition Theorem.
</span><span>H2 has 5 degrees of freedom; 3 translations and 2 rotation
</span>Therefore:
Internal energy = (5/2) nRT
You just substitute in the equation with the values of R and T and calculate the internal energy as follows:
Internal energy = (5/2) x 2 x <span>8.314 x 308 = 32.0089 x 10^3 J</span>
4 0
3 years ago
The additional product of the nuclear fission reaction shown in the
Arada [10]
The answer to your question is C.
8 0
3 years ago
A ball rolls off a desk at a speed of 3 m/s and lands .40 seconds later. How far from the base of the desk does the ball land?
Salsk061 [2.6K]

Is the velocity constant? Is there any friction?

3 meters per second

then after 40 seconds it must 3*40 = 120 meters

120 meters or 0.12 km if you will

7 0
3 years ago
Other questions:
  • In the equilibrium position, the 30-kg cylinder causes a static defl ection of 50 mm in the coiled spring. If the cylinder is de
    6·1 answer
  • Which of the following elements of writing is defined as the choice of words sulted to the type of writing?
    5·2 answers
  • If a motorcycle accelerates uniformly from rest at 5 m / s2, how long does it take for it to reach a speed of 20 m / s.
    8·1 answer
  • Distinguish between resultant and equilibrant forces<br><br><br>​
    5·1 answer
  • Which type of electromagnetic waves has highest frequency​
    5·2 answers
  • What is the first step in the event of a fire in a building?
    12·2 answers
  • The purpose of a cell phone cover is to protect your phone from impact forces. How does a cell phone case do this?
    8·1 answer
  • A car is filled up with 20 gallons of gas. The car uses .25 gallons per minute. How much time will the car travel ?​
    5·1 answer
  • A spring stretches 2 meters when a 12 N force is acting on it. What is the spring constant (k)? 10 N/m 0.17 N/m 2 N/m 6 N/m
    13·1 answer
  • What are the properties of glass in relation to microscopy?
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!