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3 years ago

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If the astronaut throws the tool with a force of 16.0 n , what is the magnitude of the acceleration a of the astronaut during th

e throw? assume that the total mass of the astronaut after she throws the tool is 80.0 kg . express your answer in meters per second squared.

2 answers:

Drupady [299]3 years ago

7 0

The magnitude of the acceleration of the astronaut : <u>0.2 m/s²</u>

<h3>Further explanation </h3>

Newton's 2nd law explains that the acceleration produced by the resultant force on an object is proportional and in line with the resultant force and inversely proportional to the mass of the object

∑F = m. a

$\large {\boxed {\bold {a = \frac {\sum F} {m}}}$

F = force, N

m = mass = kg

a = acceleration due to gravity, m / s²

the astronaut throws the tool with a force of 16.0 N ⇒ F = 16 N

the total mass of the astronaut after she throws the tool is 80.0 kg

⇒ m = 80 kg

magnitude of the acceleration of the astronaut during the throw

$\rm a=\dfrac{F}{m}\\\\a=\dfrac{16\:N}{80\:kg}\\\\a=\boxed{\bold{0.2\:\dfrac{m}{s^2}}}$

<h3>Learn more </h3>

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Maksim231197 [3]3 years ago

4 0

From Newton’s second law of motion, the value of the force is calculated by multiplying the mass and the acceleration as,

<span> F = mass x acceleration</span>

If we substitute the known values into the equation,

<span> 16 N = 80 kg x acceleration</span>

<span> Acceleration = 0.2 m/s<span>2</span></span>

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Explanation:

From the question we are told that

The weight in air is $W_a = 40 \ N$

The weight in water is $W_w = 20 \ N$

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Now according to Archimedes principle the weight of the object in water is mathematically represented as

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substituting value

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$m_w g = 20 \ N --- (1)$

Now according to Archimedes principle the weight of the object in unknown is mathematically represented as

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substituting value

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dividing equation 2 by equation 1

$\frac{m_ug}{m_wg} = \frac{10}{20}$

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Now since the volume of water and liquid displaced are the same then

$\rho _u = 0.5 \rho_w$

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Where $\rho_u$ is the density of the liquid

and $\rho_ w$ is the density of water which is a constant with a value $\rho_w = 1000 kg/m^3$

So

$\rho_u = 1000*0.5$

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