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natita [175]
3 years ago
5

A plane is traveling 600 miles. It takes the plane 5 hours against the wind and 4 hours with the wind. What is the speed of the

plane in still air, and what is the speed of the wind?
Mathematics
1 answer:
madam [21]3 years ago
6 0

Answer: the speed of the plane in still air is 135 miles per hour

the speed of the wind is 15 miles per hour

Step-by-step explanation:

Let x represent the speed of the plane in still air

Let y represent the speed of the wind.

The distance travelled by the plane is 600 miles.

Distance travelled = speed × time

It takes the plane 5 hours against the wind. This means that the total speed is (x-y) miles per hour. Therefore,

600 = 5(x- y) = 5x - 5y - - - - - - - 1

It takes the plane 4 hours with the wind. This means that the total speed is (x+y) miles per hour. Therefore,

600 = 4(x+ y) = 4x + 4y - - - - - - - - 2

Multiplying equation 1 by 4 and equation 2 by 5, it becomes

2400 = 20x - 20y

3000 = 20x + 20y

Adding both equations

5400 = 40x

x = 5400/40 = 135

Substituting x = 135 into equation 1, it becomes

4 × 135 + 4y = 600

540 + 4y = 600

4y = 600 - 540 = 60

y = 60/4 = 15

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Arte-miy333 [17]
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Step 1: 17 - 9 = 8

Step 2: 8 + 4 = 12

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Hope this helps!!

<h2>- Carmelle -</h2>
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2 years ago
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x+4y=17 and -x-6y=-23 what's the x and y I really badly need this I need this so I can play at my basketball game tommorw and I
loris [4]

<u>Answer:</u>

  • x = 5
  • y = 3

<u>Solution:</u>

  • => x + 4y = 17

            -x - 6y = -23

  • => -2y = -6
  • => y = 3

<u>Now, let's substitute the value of y into the first equation.</u>

  • x + 4y = 17
  • => x + 4(3) = 17
  • => x + 12 = 17
  • => x = 5

<u>Let's check our answer to make sure it is correct.</u>

<u>Check:</u>

  • -x - 6y = -23
  • => -(5) - 6(3) = -23
  • => -5 - 18 = -23
  • => -23 = -23

Hence, this is proven correct.

Hoped this helped.

BrainiacUser1357

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2 years ago
−6p = 48<br> what does p equal
sammy [17]
-6p=48
/-6. /-6
P=-8

P equals -8
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Foil: (x+9)(3x-4)
QveST [7]

QUESTION 1

The given binomial is;

(x+9)(3x-4)

First terms are multiplied: x\times 3x=3x^2

Outside terms are multiplied: x\times -4=-4x

Inside terms are multiplied: 9\times 3x=27x

Last terms are Multiplied: 9\times -4=-36

This gives us;

=3x^2-4x+27x-36

=3x^2+23x-36

QUESTION 2

We want to factor

6r^5s+4r^4s^2-8r^2s

The HCF is 2r^2s

We factor to get;

2r^2s(3r^3+2r^2s-4)

QUESTION 3;

x^2+x-2=0

Split the middle term;

x^2+2x-x-2=0

Factor

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(x+2)(x-1)=0

(x+2)=0,(x-1)=0

x=-2,x=1

The solutions are;

x=-2 and x=1

These are the x-intercepts of the graph of the function

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The equation that passes through (3,6) and is perpendicular to 3x - 4y = - 2
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Answer:

A. y=-5/3x+1

Step-by-step explanation:

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