Given:
Claire is 2 year younger than her sister.
The sum of ages is no less than 44 years.
To find:
Inequality and find the youngest age Claire can be.
Solution:
Let the age of Claire be x.
Her sister's age = x+2
Sum of their ages is no less than 44 years. It means the sum ages is greater than or equal to 44.
Divide both sides by 2.
It means, Claire age can be greater than or equal to 21. So, the youngest age Claire can be 21 years old.
Therefore, the required inequality is and the correct option is B.
B should be correct
Hope that helped
Answer:
m = 44
Step-by-step explanation:
USe the pythagoream thyroem a^2 + b^2 = m^2. so 10^2 + m = 12^2
or 100 + m = 144. subtract 100 from both sides, you get m = 44
Let b = blue marbles
y = yellow marbles
Sum = b+y
The <span>chance of a blue marble being drawn first is:
b / (b+y) = 0.55
</span>The <span>chance of a blue marble being drawn first then a yellow next is:
</span>b / (b+y) * <span>y / (b+y-1) = 0.37</span>
This can be solve easily by using a theorem of Bayes
0.37/0.55 = .67 or 67%
So, let's make these two values improper fractions so they're easier to work with. 
So, to get the rate he grew in those months we have:
And to get the rate he grew in one month we have to divide both our numerator and our denominator by 21 to get:
aka he grew 1.24 inches in a month.
