<span>f(x)=f(x−1)+2 this is one example =)</span>
We can say that exchanging one couple's ticket for an individual's ticket would increase the money in the cash box from 200 to 202 and it would result in an even number of couples tickets sold.
<u>Step-by-step explanation:</u>
Let the number of tickets sold to the individuals = s
Let the number of tickets sold to the couples = c
According to the question,
s + c = 46 ( Equation 1)
Since each individual's ticket is $6, the total amount of money made by selling tickets to individuals is 6s.
Similarly, since each ticket sold to couples is $8, the total amount of money made by selling tickets to couples is 8c.
So,
6 s + 8 c = 200 ( Equation 2)
On solving both the equations, we get
c = 38 and s = 8
Therefore, 8 tickets were sold to individuals and 38 tickets were sold to the couples.
Answer:
15 and 1
Step-by-step explanation:
x and y are two numbers.
Two equations:
x · y = 15
x + y = 16
Rearrange one of the equations (I'll rearrange the sum equation):
x + y = 16
x = 16 - y
Substitute that to the other equation and solve for y:
x · y = 15
(16 - y) · y = 15
16 - y · y = 15
16 - y² = 15
-y² = 15 - 16
-y² = -1
y² = 1
y = √1
y = 1
Now substitute that to any of the equation and solve for x (in here, I'll choose the multiplication one):
x · y = 15
x · 1 = 15
x = 15
Now verify:
15 · 1 = 15
15 + 1 = 16
This is correct
Answer:ratio
Step-by-step explanation:
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Let x equal the number of tiny book boxes and y equal the number of large book boxes.
Because John must pack at least 35 boxes:
(number of tiny book boxes) + (number of large book boxes) = (at least) 35
x + y ≥ 35
Since John needs to pack at least 350 books:
(number of small books packed) + (number of large books packed) (is at least) 350
(number of small books per box)(number of boxes of small books) + (number of large books per box)(number of boxes of small books) ≥ 350
15x + 8y ≥ 350
Your system of inequalities is:
x + y ≥ 35
15x + 8y ≥ 350
<h2>GO INTO DESMOS TO GRAPH</h2>
