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grin007 [14]
3 years ago
14

HELP! According to the Fundamental Theorem of Algebra, which polynomial function has exactly 11 roots?

Mathematics
2 answers:
IceJOKER [234]3 years ago
8 0

Answer:

A.

Step-by-step explanation:

antiseptic1488 [7]3 years ago
3 0
The one where x is raised to the 11 power.
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10) Solve using any method<br> 10x+2y=42<br> 5x+y=20
KIM [24]

Answer:

no solutions

Step-by-step explanation:

10x+2y=42

5x+y=20

Multiply the second equation by -2 to use elimination

-2(5x+y)=20*-2

-10x -2y = -40

Add this to the first equation

10x+2y=42

-10x -2y = -40

--------------------------

0 = 2

This is never true.  This means there are no solutions

3 0
3 years ago
Read 2 more answers
Task;2round off the following numbers to the highest place value.
eimsori [14]

Answer:

1.) 434 ____________

2.)5658 ____________

3.) 8374 ____________

4.) 361 ____________

5.) 7454 ____________

ito po ba ang i raround off

Step-by-step explanation:

answer:

1. 400

2.5000

3.8000

4.400

5.7000

kung ito po

#HOPE ITS HELP

7 0
2 years ago
Expression when m=8 and n=7 n+6m
Andrews [41]
All you have to do is plug m and n into the equation:

n+6m

Since n=7, you'll get:

7+6m

And since m=8, you'll get:

7+6(8)

And by doing the order of operations (PEMDAS), you'll start off multiplying 6 and 8, which is 48, then add 7, which is 55.

Your answer should be 55!
7 0
3 years ago
Read 2 more answers
A professor has recorded exam grades for 10 students in his​ class, but one of the grades is no longer readable. If the mean sco
Nostrana [21]

Answer:

unreadable score = 35

Step-by-step explanation:

We are trying to find the score of one exam that is no longer readable, let's give that score the name "x". we can also give the addition of the rest of 9 readable s scores the letter "R".

There are two things we know, and for which we are going to create equations containing the unknowns "x", and "R":

1) The mean score of ALL exams (including the unreadable one) is 80

so the equation to represent this statement is:

mean of ALL exams = 80

By writing the mean of ALL scores (as the total of all scores added including "x") we can re-write the equation as:

\frac{R+x}{10} =80

since the mean is the addition of all values divided the total number of exams.

in a similar way we can write what the mean of just the readable exams is:

\frac{R}{9} = 85\\ (notice that this time we don't include the grade x in the addition, and we divide by 9 instead of 10 because only 9 exams are being considered for this mean.

Based on the equation above, we can find what "R" is by multiplying both sides by 9:

\frac{R}{9} = 85\\R=85*9= 765

Therefore we can now use this value of R in the very first equation we created, and solve for "x":

\frac{R+x}{10} =80\\\frac{765+x}{10} =80\\765+x=80*10=800\\765+x=800\\x=800-765=35

4 0
3 years ago
Helppppppppppppppppppp
nignag [31]
I think it’s the fourth one!!
6 0
3 years ago
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