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grin007 [14]
3 years ago
14

HELP! According to the Fundamental Theorem of Algebra, which polynomial function has exactly 11 roots?

Mathematics
2 answers:
IceJOKER [234]3 years ago
8 0

Answer:

A.

Step-by-step explanation:

antiseptic1488 [7]3 years ago
3 0
The one where x is raised to the 11 power.
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7(6m - 4) = -364 pls try and show work thanks!
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Answer:

7(6m - 4) = -364

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The equation of a quadratic is =2^2+3−2and after you factorizing 2^2+3−2=0you got x = -2 and x = 1/2 and the curve crosses the y
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Given the next quadratic function:

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The y-coordinate of the vertex is found by substituting the x-coordinate in the quadratic function, as follows:

\begin{gathered} y_V=2x^2_V+3x_V-2 \\ y_V=2\cdot(-\frac{3}{4})^2+3\cdot(-\frac{3}{4})-2 \\ y_V=2\cdot\frac{9}{16}+3\cdot(-\frac{3}{4})-2 \\ y_V=\frac{9}{8}-\frac{9}{4}-2 \\ y_V=-\frac{25}{8}=-3.125 \end{gathered}

The factorization indicates that the curve crosses the x-axis at the points (-2, 0) and (1/2, 0). We also know that the curve crosses the y-axis at (0,-2). Connecting these points and the vertex (-0.75, -3.125) with a U-shaped curve, we get:

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

3 is less than 3.58

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