All categories

3 years ago

HELP! According to the Fundamental Theorem of Algebra, which polynomial function has exactly 11 roots?

Mathematics

2 answers:

IceJOKER [234]3 years ago

8 0

Answer:

Step-by-step explanation:

antiseptic1488 [7]3 years ago

3 0

The one where x is raised to the 11 power.

You might be interested in

A 500-kg car has 25,000 joules of kinetic energy. What is its speed?

Lelu [443]

(m.v^2)/ 2 = 25000
<=> 500.v^2 = 50000
<=> v^2 = 100
<=> v = 10 m/s

7 0

3 years ago

3(x+3)+3x=15<br><br> Solution and check<br><br> Shown in attachment below

OLga [1]

3x + 9 + 3x =15
6x + 9 = 15
- 9 = -9
6x = 6
/6 /6

X =1

6 0

3 years ago

30 POINTS AVAILABLE

kherson [118]

Answer:

$\large\boxed{(x-2)^2+(y-1)^2=34}$

Step-by-step explanation:

The equation of a circle in standard form:

$(x-h)^2+(y-k)^2=r^2$

(h, k) - center

r - radius

We have the endpoints of the diameter: (-1, 6) and (5, -4).

Midpoint of diameter is a center of a circle.

The formula of a midpoint:

$\left(\dfrac{x_1+x_2}{2};\ \dfrac{y_1+y_2}{2}\right)$

Substitute:

$h=\dfrac{-1+5}{2}=\dfrac{4}{2}=2\\\\k=\dfrac{6+(-4)}{2}=\dfrac{2}{2}=1$

The center is in (2, 1).

The radius length is equal to the distance between the center of the circle and the endpoint of the diameter.

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute the coordinates of the points (2, 1) and (5, -4):

$r=\sqrt{(5-2)^2+(-4-1)^2}=\sqrt{3^2+(-5)^2}=\sqrt{9+25}=\sqrt{34}$

Finally we have:

$(x-2)^2+(y-1)^2=(\sqrt{34})^2$

3 0

3 years ago

Can someone help me with these word problems?

Jobisdone [24]

1) $375
500 *.25= 125
500-125= 375

2) (5/8)* 32= 20 girls in class
(3/8)* 32= 12 BOYS in class

4) 19+42+X=87
62+X= 87 (add 19 and 42 together )
X=25 ( subtract 87 from 62)

4 0

3 years ago

how to make a 89 inch snow man with a three balls of snow at the top piece 3 pieces 8 inches 3 inches and 7.09 inches now with a

oksano4ka [1.4K]

The answer is 112.09 i added 89+3+3+8+2=105+7.09=112.09

4 0

3 years ago