The total distance traveled by the robot from t=0 to t=9 is 1422 units
Integration is a way in which smaller components are brought together in pieces to form a whole. Integration can be used in finding areas, volumes and so on.
Given that the position s(t) at any time t is given by the function:
s(t)=9t²−90t+4
The total distance traveled by the robot from t=0 to t=9 can be gotten by integrating the position function within the limits 0< t < 9
Therefore:
![Total\ distance = \int\limits^9_0 {s(t) \, dt \\\\Total\ distance = \int\limits^9_0 {(9t^2-90t+4) \, dt\\\\Total\ distance = [3t^3-45t+4t]_0^9\\\\Total\ distance=-1422\ units](https://tex.z-dn.net/?f=Total%5C%20distance%20%3D%20%5Cint%5Climits%5E9_0%20%7Bs%28t%29%20%5C%2C%20dt%20%5C%5C%5C%5CTotal%5C%20distance%20%3D%20%5Cint%5Climits%5E9_0%20%7B%289t%5E2-90t%2B4%29%20%5C%2C%20dt%5C%5C%5C%5CTotal%5C%20distance%20%3D%20%5B3t%5E3-45t%2B4t%5D_0%5E9%5C%5C%5C%5CTotal%5C%20distance%3D-1422%5C%20units)
The total distance is 1422 units
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Answer:
P = 16
Step-by-step explanation:
Given
5W = 2P + 3R ← substitute W = 4 and R = - 4 into the equation
5(4) = 2P + 3(- 4), that is
20 = 2P - 12 ( add 12 to both sides )
32 = 2P ( divide both sides by 2 )
16 = P
Answer:
35/4 minutes per mile
Step-by-step explanation:
rate = time/distance, therefore the answer is 35/4
Are you sure it is correct because for each one your just doubling the number. 2+2=4. 4+4=8. 8+8=16. I think its suppose to be 16+16= 32 and so on, but I may be wrong