All categories

3 years ago

(f+g)(4)I really don't know what to do?? or how to start ??

Mathematics

1 answer:

olganol [36]3 years ago

8 0

$(f+g)(x)=x^2-2x+2+1-3x=x^2-5x+3\\\\ (f+g)(4)=4^2-5\cdot4+3=16-20+3=-1$

You might be interested in

Please help me on this

seropon [69]

Answer:

the answers are A D and E

4 0

3 years ago

7nadin3 [17]

Answer:

1.5 because it is the average of the two middle numbers in this scenario.

7 0

3 years ago

The equation d=10h represents the number of miles d that Jin travels in h hours . If Jon cuts down the time it takes to travel 3

ahrayia [7]

0.15 is multiplied by 10 = 1.5 hours

5 0

3 years ago

What are the domain and range of the function 2 y x x    6 8 shown in the graph below?

Nat2105 [25]

Answer:

Missing information.

Step-by-step explanation:

However, the domain is all the x- values. The range is all the y-values (that do not repeat).

So when you look at your graph, find your x values and y-values and write them as set. That is your answer.

7 0

3 years ago

how to integrate <img src="https://tex.z-dn.net/?f=e%5E%7B2s%7D%20%2ACos%20%5Cfrac%7Bs%7D%7B4%7D" id="TexFormula1" title="e^{2s}

icang [17]

Answer:

$\int\limits {e^{2s} cos\frac{s}{4} ds$ = $\frac{4 e^{2s} }{65 } ({8 cos (\frac{1}{4} ) s + sin \frac{1}{4} s} ))$

Step-by-step explanation:

Step(i):-

Given that $f(s) = e^{2s} cos\frac{s}{4}$

Now integrating

$\int\limits {f(s)} \, ds = \int\limits {e^{2s} cos\frac{s}{4} ds$

By using integration formula

$\int\limits { e^{ax} cos b x dx = \frac{e^{ax} }{a^{2}+b^{2} } ( a cos b x + b sin b x )$

Step(ii):-

$\int\limits {e^{2s} cos\frac{s}{4} ds$ = $\frac{e^{2s} }{(2)^{2}+(\frac{1}{4}) ^{2} } ( 2 cos (\frac{1}{4} ) s + \frac{1}{4} sin \frac{1}{4} s ))$

= $\frac{e^{2s} }{(4+\frac{1}{16})} ( 2 cos (\frac{1}{4} ) s + \frac{1}{4} sin \frac{1}{4} s ))$

= $\frac{e^{2s} }{(\frac{65}{16} } ( \frac{8 cos (\frac{1}{4} ) s + sin \frac{1}{4} s}{4} ))$

= $16 X\frac{e^{2s} }{65 } ( \frac{8 cos (\frac{1}{4} ) s + sin \frac{1}{4} s}{4} ))$

= $\frac{4 e^{2s} }{65 } ({8 cos (\frac{1}{4} ) s + sin \frac{1}{4} s} ))$

Final answer:-

$\int\limits {e^{2s} cos\frac{s}{4} ds$ = $\frac{4 e^{2s} }{65 } ({8 cos (\frac{1}{4} ) s + sin \frac{1}{4} s} ))$

6 0

3 years ago