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3 years ago

How much does a cat way on the moon

Mathematics

1 answer:

Gwar [14]3 years ago

5 0

Answer:

Since weight is directly dependent on the acceleration of gravity, things on the Moon will weigh only 16.6% (≈ 1/6) of their weight on Earth.

Step-by-step explanation:

Being that the moon has a gravitational force of 1.622m/s2, we multiply the object's mass by this quanitity to calculate an object's weight on the moon. So an object or person on the moon would weigh 16.5% its weight on earth. Therefore, a person would be much lighter on the moon.

have a nice day /night\

may i please have a branlliest

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There are 4 prime numbers

amid [387]

Answer:

Step-by-step explanation:

As you go to larger numbers, there are more possibilities of factors for them.

For example, the internal from 20 to 30 contains only two prime numbers (23 and 29) and the interval from 90 to 100 contains only one prime (97).

However, the number of prime numbers in an interval varies. There are four prime numbers between 100 and 110 (101, 103, 107, 109).

4 0

4 years ago

A spherical balloon currently has a radius of 19cm. If the radius is still growing at a rate of 5cm or minute, at what rate is a

miv72 [106K]

Answer:

22670.8 cm³/min

Step-by-step explanation:

Given:

Radius of the balloon at a certain time (r) = 19 cm

Rate of growth of radius is, $\frac{dr}{dt}=5\ cm/min$

The rate at which the air is pumped in the balloon can be calculated by finding the rate of increase in the volume of the balloon.

So, first we find the volume of the sphere in terms of 'r'. As the balloon is spherical in shape, the volume of the balloon is equal to the volume of a sphere. Therefore,

Volume of balloon is given as:

$V=\frac{4}{3}\pi r^3$

Now, rate of increase of volume is obtained by differentiating both sides of the equation with respect to time 't'.

Differentiating both sides with respect to time 't', we get:

$\frac{dV}{dt}=\frac{d}{dt}(\frac{4}{3}\pi r^3)\\\\\frac{dV}{dt}=\frac{4\pi}{3}(3r^2)(\frac{dr}{dt})\\\\\frac{dV}{dt}=4\pi r^2(\frac{dr}{dt})$

Now, plug in 19 cm for 'r', 5 cm per minute for $\frac{dr}{dt}$ and solve for $\frac{dV}{dt}$ . This gives,

$\frac{dV}{dt}=4\pi (19 cm)^2(5\ cm/min)\\\\\frac{dV}{dt}=4\times 3.14\times 361\times 5\ cm^3/min\\\\\frac{dV}{dt}=22670.8\ cm^3/min$

Therefore, the rate at which the air is being pumped into the balloon is 22670.8 cm³/min.

4 0

4 years ago

Which function has a constant additive rate of change of -1/4?

VladimirAG [237]

Answer:

The first graph (in other words A)

Step-by-step explanation:

bc it is going down 1/4 at a constant rate!!!

Hope This Helps!!!

7 0

3 years ago

Question is in image below

skad [1K]

Answer:

15 ft.

Step-by-step explanation:

I will assume that either both objects are standing straight. We can use similar triangles.

We can see that the side 8 is similar to the side 20, since they are both shadows. Therefore, we can set up an equation:

$\frac{6}{8} =\frac{x}{20}$

we can cross multiply and get:

8x=120

solve for x:

x=15

Therefore, the lamppost must be 15 feet tall (unless it fell down but we won't talk about that)

4 0

3 years ago

Joy decided to ride her bike to visit her friend, Three miles from home her bike got a flat tire and she had to walk the remaini

ICE Princess25 [194]

Answer:

Step-by-step explanation:

okay, so she rode 3 miles. Keep that aside

Then she had 2 walk the remaining 2 miles

She had to walk all the way home. So say for example instead of riding she walked 3 miles, then she walked that additional 2 miles. So, 5 miles. Then add the two miles she had to walk to his house. so, she walked 7 miles and rode 3 miles. 7-3= <em>4</em> miles. I attached a picture that should hopefully explain it better.

Hope this helps!

7 0

2 years ago