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3 years ago

Which is a true statement?

Mathematics

2 answers:

myrzilka [38]3 years ago

8 0

B is correct because -6.75 is smaller than -6.5

dangina [55]3 years ago

4 0

<span>b is correct because -6.75 is smaller than -6.5 </span>

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Which inequality is true when the value of d is −13?

lesya [120]

Answer:

A. -5 - 3(6) > 10

13 > 10

Step-by-step explanation:

8 0

3 years ago

Suppose that a family wants to start a college fund for their child. If they can get a rate of 5.5% , compounded monthly, and wa

Angelina_Jolie [31]

In 20 years a family will be able to earn 35 450 dollars. The interest that they earned is 5.5% compounded monthly. Now, let's find out how much will they need to save monthly to get this amount in 20 year:
=> 12 * 20 = 240 months
=> 35 450 / 240 months = 147.7 dollars per month is the money with interest
Let's subtract the interest
=> 147.7 * 0.055 = 8.1 dollars.
=> 147.7 - 8.1 = 139.6 dollars per month.

3 0

4 years ago

Read 2 more answers

Candy. Someone hands you a box of a dozen chocolate-covered candies, telling you that half are vanilla creams and the other half

BaLLatris [955]

Answer:

a) P=0.091

b) If there are half of each taste, picking 3 vainilla in a row has a rather improbable chance (9%), but it is still possible that there are 6 of each taste.

c) The probability of picking 4 vainilla in a row, if there are half of each taste, is P=0.030.

This is a very improbable case, so if this happens we would have reasons to think that there are more than half vainilla candies in the box.

Step-by-step explanation:

We can model this problem with the variable x: number of picked vainilla in a row, following a hypergeometric distribution:

$P(x=k)=\dfrac{\binom{K}{k}\cdot \binom{N-K}{n-k}}{\binom{N}{n}}$

being:

N is the population size (12 candies),

K is the number of success states in the population (6 vainilla candies),

n is the number of draws (3 in point a, 4 in point c),

k is the number of observed successes (3 in point a, 4 in point c),

a) We can calculate this as:

$P(x=3)=\dfrac{\binom{6}{3}\cdot \binom{12-6}{3-3}}{\binom{12}{3}}=\dfrac{\binom{6}{3}\cdot \binom{6}{0}}{\binom{12}{3}}=\dfrac{20\cdot 1}{220}=0.091$

b) If there are half of each taste, picking 3 vainilla in a row has a rather improbable chance (9%), but is possible.

c) In the case k=4, we have:

$P(x=3)=\dfrac{\binom{6}{4}\cdot \binom{6}{0}}{\binom{12}{4}}=\dfrac{15\cdot 1}{495}=0.030$

This is a very improbable case, so we would have reasons to think that there are more than half vainilla candies in the box.

4 0

3 years ago

Find the probability of 2 heads when flipping 3 coins

Olegator [25]

2/6 is the answer 1/2 1/2 0/2

7 0

3 years ago

Read 2 more answers

Devante buys 1/1/4 pounds of cashews 7 ounces of almonds and 3/4 pounds of pecans how much do the nuts weight in

liberstina [14]

Answer: $39\ \text{Ounces}$

Step-by-step explanation:

Given

The amount of cashews is $1\frac{1}{4}\ \text{Pounds}$

Amount of almonds $7\ \text{ounces}$

The amount of pecans is $\frac{3}{4}\ \text{Pounds}$

We know, $1\ \text{Pound}=16\ \text{Ounces}$

Converting pounds to ounces and adding them

$\Rightarrow 1\dfrac{1}{4}\times 16+7+\dfrac{3}{4}\times 16\\\\\Rightarrow \dfrac{5}{4}\times 16+7+3\times 4\\\\\Rightarrow 20+7+12=39\ \text{ounces}\ or\ \dfrac{39}{16}\ \text{Pounds}$

Thus, the nuts weigh $39\ \text{Ounces}$

6 0

3 years ago