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2 years ago

Which equation is an identity?

Mathematics

2 answers:

Yakvenalex [24]2 years ago

8 0

C. 3w + 8 - w = 4w - 2(w - 4)

(3w - w) + 8 = 4w - 2w -2(-4)

2w + 8 = 2w + 8

Andrews [41]2 years ago

5 0

I think
C. 3w+8-w=4w-2(w-4)

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Please find the surface area of the pyramid... I will mark you brainliest

Brut [27]

Answer:

S.A. = 704 in²

Step-by-step explanation:

Surface area (S.A. ) = 1/2 lp + B where l is the slant height , p is the perimeter of the base, and B is the area of the base .

Given l = 14; The Base figure is a square so the p = 4· side = 4 · 16 = 64 and the area of the Base = s² = 256

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1 year ago

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3 years ago

Read 2 more answers

How would I do part A. I showed my work but I'm slightly off

ahrayia [7]

$\bf \stackrel{\textit{perimeter of the rectangle}}{P_{rect}=2x+y}~\hfill \stackrel{\textit{area of the rectangle}}{A_{rect}=xy}
\\\\\\
\stackrel{\textit{perimeter of the semi-circle, with }r=\frac{y}{2}}{P_{semic}=\cfrac{\pi y}{2}}~\hfill \stackrel{\textit{area of the semi-circle with }r=\frac{y}{2}}{A_{semic}=\cfrac{\pi y^2}{8}}
\\\\[-0.35em]
\rule{34em}{0.25pt}$

$\bf \stackrel{\textit{perimeter of the enclosure}}{60=2x+y+\cfrac{\pi y}{2}}\implies \stackrel{\textit{multiplying by 2}}{120=4x+2y+\pi y}
\\\\\\
120-2y-\pi y=4x\implies \cfrac{120-2y-\pi y}{4}=x
\\\\[-0.35em]
\rule{34em}{0.25pt}$

$\bf \stackrel{\textit{area of the enclosure}}{A=xy+\cfrac{\pi y^2}{8}}\implies A=\left( \cfrac{120-2y-\pi y}{4} \right)y+\cfrac{\pi y^2}{8}
\\\\\\
A=\cfrac{120y-2y^2-\pi y^2}{4}+\cfrac{\pi y^2}{8}\implies A=\cfrac{240y-4y^2-2\pi y^2+\pi y^2}{8}
\\\\\\
A=\cfrac{240y-4y^2-\pi y^2}{8}\implies A=\cfrac{240y}{8}-\cfrac{4y^2}{8}-\cfrac{\pi y^2}{8}
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
~\hfill A=30y-\cfrac{1}{2}y^2-\cfrac{1}{8}\pi y^2~\hfill$

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3 years ago

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Anestetic [448]

Answer:

Kindly check explanation and attached picture

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Given the time-series data:

Time (x) : 1 - - 2 - - 3 - - - 4 - - - 5

Data (yt) :6 - - 11 - - 9 - - 14 - - 15

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